#!/bin/sh# mdate-sh - get modification time of a file and pretty-print it# Copyright (C) 1995 Software Foundation, Inc.# Written by Ulrich Drepper <drepper@gnu.ai.mit.edu>, June 1995## This program is free software; you can redistribute it and/or modify# it under the terms of the GNU General Public License as published by# the Free Software Foundation; either version 2, or (at your option)# any later version.## This program is distributed in the hope that it will be useful,# but WITHOUT ANY WARRANTY; without even the implied warranty of# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the# GNU General Public License for more details.## You should have received a copy of the GNU General Public License# along with this program; if not, write to the Free Software# Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.# Prevent date giving response in another language.LANG=Cexport LANGLC_ALL=Cexport LC_ALLLC_TIME=Cexport LC_TIME# Get the extended ls output of the file.if ls -L /dev/null 1>/dev/null 2>&1; then  set - `ls -L -l $1`else  set - `ls -l $1`fi# The month is at least the fourth argument.# (3 shifts here, the next inside the loop)shiftshiftshift# Find the month.  Next argument is day, followed by the year or time.month=until test $monthdo  shift  case $1 in    Jan) month=January; nummonth=1;;    Feb) month=February; nummonth=2;;    Mar) month=March; nummonth=3;;    Apr) month=April; nummonth=4;;    May) month=May; nummonth=5;;    Jun) month=June; nummonth=6;;    Jul) month=July; nummonth=7;;    Aug) month=August; nummonth=8;;    Sep) month=September; nummonth=9;;    Oct) month=October; nummonth=10;;    Nov) month=November; nummonth=11;;    Dec) month=December; nummonth=12;;  esacdoneday=$2# Here we have to deal with the problem that the ls output gives either# the time of day or the year.case $3 in  *:*) set `date`; eval year=\$$#       case $2 in	 Jan) nummonthtod=1;;	 Feb) nummonthtod=2;;	 Mar) nummonthtod=3;;	 Apr) nummonthtod=4;;	 May) nummonthtod=5;;	 Jun) nummonthtod=6;;	 Jul) nummonthtod=7;;	 Aug) nummonthtod=8;;	 Sep) nummonthtod=9;;	 Oct) nummonthtod=10;;	 Nov) nummonthtod=11;;	 Dec) nummonthtod=12;;       esac       # For the first six month of the year the time notation can also       # be used for files modified in the last year.       if (expr $nummonth \> $nummonthtod) > /dev/null;       then	 year=`expr $year - 1`       fi;;  *) year=$3;;esac# The result.echo $day $month $year