?? subtractrect.htm
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<title>SubtractRect</title>
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<td width="100%" height="16"><a name="SubtractRect">SubtractRect</a></td>
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<td width="100%" colspan="2">VB聲明</td>
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<td width="100%" colspan="2">Declare Function SubtractRect Lib "user32" Alias
"SubtractRect" (lprcDst As RECT, lprcSrc1 As RECT, lprcSrc2 As RECT) As Long</td>
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<td width="100%" colspan="2">說明</td>
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<td width="100%" colspan="2">這個函數會裝載矩形lprcDst，它是在矩形lprcSrc1中減去lprcSrc2得到的結果</td>
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<td width="100%" colspan="2">返回值</td>
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<td width="100%" colspan="2">Long，TRUE（非零）表示成功，零表示失敗</td>
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<td width="100%" colspan="2">參數表</td>
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<td width="25%">參數</td>
<td width="75%">類型及說明</td>
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<td width="25%">lprcDst</td>
<td width="75%"><a href="RECT.htm">RECT</a>，準備包容lprcSrc1減lprcSrc2結果的目標矩形</td>
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<td width="25%">lprcSrc1</td>
<td width="75%"><a href="RECT.htm">RECT</a>，第一個源矩形</td>
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<td width="25%">lprcSrc2</td>
<td width="75%"><a href="RECT.htm">RECT</a>，第二個源矩形</td>
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<td width="100%" colspan="2">注解</td>
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<td width="100%" colspan="2"><p align="left">lprcSrc1與lprcSrc2這兩個矩形必須在水平或垂直方向完全相交。換句話說，倘若在lprcSrc1中拿掉與lprcSrc2相交的lprcDst部分，結果必須是個矩形</td>
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<td width="100%"><p align="right"><a href="#SubtractRect">Top</a></td>
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