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<TD class=zi width=562 valign="middle"><b><font color="#ffffff">.:.:經典c程序100例==31--40:.:.</font></b></TD>
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<p align="left"><font color="#FF9933"><b><font size="5"> <font color="#3300CC">經典c程序100例==31--40</font></font></b></font></p>
<p><font color="#990000">【程序31】</font><br>
題目：請輸入星期幾的第一個字母來判斷一下是星期幾，如果第一個字母一樣，則繼續<br>
判斷第二個字母。<br>
1.程序分析：用情況語句比較好，如果第一個字母一樣，則判斷用情況語句或if語句判斷第二個字母。<br>
2.程序源代碼：<br>
#include <stdio.h><br>
void main()<br>
{<br>
char letter;<br>
printf("please input the first letter of someday\n");<br>
while ((letter=getch())!='Y')/*當所按字母為Y時才結束*/<br>
{ switch (letter)<br>
{case 'S':printf("please input second letter\n");<br>
if((letter=getch())=='a')<br>
printf("saturday\n");<br>
else if ((letter=getch())=='u')<br>
printf("sunday\n");<br>
else printf("data error\n");<br>
break;<br>
case 'F':printf("friday\n");break;<br>
case 'M':printf("monday\n");break;<br>
case 'T':printf("please input second letter\n");<br>
if((letter=getch())=='u')<br>
printf("tuesday\n");<br>
else if ((letter=getch())=='h')<br>
printf("thursday\n");<br>
else printf("data error\n");<br>
break;<br>
case 'W':printf("wednesday\n");break;<br>
default: printf("data error\n");<br>
}<br>
}<br>
}<br>
==============================================================<br>
<font color="#990000">【程序32】</font><br>
題目：Press any key to change color, do you want to try it. Please hurry up!<br>
1.程序分析： <br>
2.程序源代碼：<br>
#include <conio.h><br>
void main(void)<br>
{<br>
int color;<br>
for (color = 0; color < 8; color++)<br>
{ <br>
textbackground(color);/*設置文本的背景顏色*/<br>
cprintf("This is color %d\r\n", color);<br>
cprintf("Press any key to continue\r\n");<br>
getch();/*輸入字符看不見*/<br>
}<br>
}<br>
==============================================================<br>
<font color="#990000">【程序33】</font><br>
題目：學習gotoxy()與clrscr()函數 <br>
1.程序分析：<br>
2.程序源代碼：<br>
#include <conio.h><br>
void main(void)<br>
{<br>
clrscr();/*清屏函數*/<br>
textbackground(2);<br>
gotoxy(1, 5);/*定位函數*/<br>
cprintf("Output at row 5 column 1\n");<br>
textbackground(3);<br>
gotoxy(20, 10);<br>
cprintf("Output at row 10 column 20\n");<br>
}<br>
==============================================================<br>
<font color="#990000">【程序34】</font><br>
題目：練習函數調用<br>
1. 程序分析： <br>
2.程序源代碼：<br>
#include <stdio.h><br>
void hello_world(void)<br>
{<br>
printf("Hello, world!\n");<br>
}<br>
void three_hellos(void)<br>
{<br>
int counter;<br>
for (counter = 1; counter <= 3; counter++)<br>
hello_world();/*調用此函數*/<br>
}<br>
void main(void)<br>
{<br>
three_hellos();/*調用此函數*/<br>
}<br>
==============================================================<br>
<font color="#990000">【程序35】</font><br>
題目：文本顏色設置<br>
1.程序分析：<br>
2.程序源代碼：<br>
#include <conio.h><br>
void main(void)<br>
{<br>
int color;<br>
for (color = 1; color < 16; color++)<br>
{<br>
textcolor(color);/*設置文本顏色*/<br>
cprintf("This is color %d\r\n", color);<br>
}<br>
textcolor(128 + 15);<br>
cprintf("This is blinking\r\n");<br>
}<br>
==============================================================<br>
<font color="#990000">【程序36】</font><br>
題目：求100之內的素數 <br>
1.程序分析：<br>
2.程序源代碼：<br>
#include <stdio.h><br>
#include "math.h"<br>
#define N 101<br>
main()<br>
{<br>
int i,j,line,a[N];<br>
for(i=2;i<N;i++) a[i]=i;<br>
for(i=2;i<sqrt(N);i++)<br>
for(j=i+1;j<N;j++)<br>
{<br>
if(a[i]!=0&&a[j]!=0)<br>
if(a[j]%a[i]==0)<br>
a[j]=0;}<br>
printf("\n");<br>
for(i=2,line=0;i<N;i++)<br>
{<br>
if(a[i]!=0)<br>
{printf("%5d",a[i]);<br>
line++;}<br>
if(line==10)<br>
{printf("\n");<br>
line=0;}<br>
}<br>
}<br>
==============================================================<br>
<font color="#990000">【程序37】</font><br>
題目：對10個數進行排序<br>
1.程序分析：可以利用選擇法，即從后9個比較過程中，選擇一個最小的與第一個元素交換，<br>
下次類推，即用第二個元素與后8個進行比較，并進行交換。 <br>
2.程序源代碼：<br>
#define N 10<br>
main()<br>
{int i,j,min,tem,a[N];<br>
/*input data*/<br>
printf("please input ten num:\n");<br>
for(i=0;i<N;i++)<br>
{<br>
printf("a[%d]=",i);<br>
scanf("%d",&a[i]);}<br>
printf("\n");<br>
for(i=0;i<N;i++)<br>
printf("%5d",a[i]);<br>
printf("\n");<br>
/*sort ten num*/<br>
for(i=0;i<N-1;i++)<br>
{min=i;<br>
for(j=i+1;j<N;j++)<br>
if(a[min]>a[j]) min=j;<br>
tem=a[i];<br>
a[i]=a[min];<br>
a[min]=tem;<br>
}<br>
/*output data*/<br>
printf("After sorted \n");<br>
for(i=0;i<N;i++)<br>
}<br>
==============================================================<br>
<font color="#990000">【程序38】</font><br>
題目：求一個3*3矩陣對角線元素之和 <br>
1.程序分析：利用雙重for循環控制輸入二維數組，再將a[i][i]累加后輸出。<br>
2.程序源代碼：<br>
main()<br>
{<br>
float a[3][3],sum=0;<br>
int i,j;<br>
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