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printf("please input rectangle element:\n");<br>
for(i=0;i<3;i++)<br>
for(j=0;j<3;j++)<br>
scanf("%f",&a[i][j]);<br>
for(i=0;i<3;i++)<br>
sum=sum+a[i][i];<br>
printf("duijiaoxian he is %6.2f",sum);<br>
}<br>
==============================================================<br>
<font color="#990000">【程序39】</font><br>
題目：有一個已經(jīng)排好序的數(shù)組。現(xiàn)輸入一個數(shù)，要求按原來的規(guī)律將它插入數(shù)組中。<br>
1. 程序分析：首先判斷此數(shù)是否大于最后一個數(shù)，然后再考慮插入中間的數(shù)的情況，插入后<br>
此元素之后的數(shù)，依次后移一個位置。 <br>
2.程序源代碼：<br>
main()<br>
{<br>
int a[11]={1,4,6,9,13,16,19,28,40,100};<br>
int temp1,temp2,number,end,i,j;<br>
printf("original array is:\n");<br>
for(i=0;i<10;i++)<br>
printf("%5d",a[i]);<br>
printf("\n");<br>
printf("insert a new number:");<br>
scanf("%d",&number);<br>
end=a[9];<br>
if(number>end)<br>
a[10]=number;<br>
else<br>
{for(i=0;i<10;i++)<br>
{ if(a[i]>number)<br>
{temp1=a[i];<br>
a[i]=number;<br>
for(j=i+1;j<11;j++)<br>
{temp2=a[j];<br>
a[j]=temp1;<br>
temp1=temp2;<br>
}<br>
break;<br>
}<br>
}<br>
}<br>
for(i=0;i<11;i++)<br>
printf("%6d",a[i]);<br>
}<br>
==============================================================<br>
<font color="#990000">【程序40】</font><br>
題目：將一個數(shù)組逆序輸出。<br>
1.程序分析：用第一個與最后一個交換。<br>
2.程序源代碼：<br>
#define N 5<br>
main()<br>
{ int a[N]={9,6,5,4,1},i,temp;<br>
printf("\n original array:\n");<br>
for(i=0;i<N;i++)<br>
printf("%4d",a[i]);<br>
for(i=0;i<N/2;i++)<br>
{temp=a[i];<br>
a[i]=a[N-i-1];<br>
a[N-i-1]=temp;<br>
}<br>
printf("\n sorted array:\n");<br>
for(i=0;i<N;i++)<br>
printf("%4d",a[i]);<br>
}</p>
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<TD id=notice vAlign=center align=left colSpan=2 height=25> <font color="#ffffff"><b>[</b>來源<b>]</b>:
不詳
<b>[</b>編輯<b>]</b>: <font color=ffffff>
beck
</font> <b>[</b>加入時間<b>]</b>:2002-8-11 </font>
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<li><font color=#0772B1>上篇文章</font>：<a href="list.asp?id=205">經(jīng)典c程序100例==21--30</a>
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<li><font color=#0772B1>下篇文章</font>：<a href="list.asp?id=207">經(jīng)典c程序100例==41--50</a>
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經(jīng)典c程序100例==91--100
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<td width="87%" align=center> 遼寧省鐵嶺師專c語言研究中心 <u>楊志鋒</u> 數(shù)學(xué)系 <u>杜博</u> </td>
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