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class=zi>點擊“保存設置”按扭可使您本次閱讀的整體設置（文字、字號、背景）得以保留，下次閱讀時您就不必再重新設置，以符合您的閱讀習慣。</TD></TR></TBODY></TABLE></TD></TR></TBODY></TABLE></DIV>
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<TD class=zi width=562 valign="middle"><b><font color="#ffffff">.:.:經(jīng)典c程序100例==21--30:.:.</font></b></TD>
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<TD class=zi vAlign=center width=308 height=25><font size="2"> 文字
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背景
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<OPTION
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<TD class=zi width=2 ><font size="2"> </font></TD>
<TD class=zi width=164><font size="2"> 人氣指數(shù)：<font color="#FF0000">31372</font>
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<p><font color="#FF9933"><b><font size="5"> <font color="#3300CC">經(jīng)典c程序100例==21--30</font></font></b></font></p>
<p><font color="#990000">【程序21】</font><br>
題目：猴子吃桃問題：猴子第一天摘下若干個桃子，當即吃了一半，還不癮，又多吃了一個<br>
第二天早上又將剩下的桃子吃掉一半，又多吃了一個。以后每天早上都吃了前一天剩下<br>
的一半零一個。到第10天早上想再吃時，見只剩下一個桃子了。求第一天共摘了多少。<br>
1.程序分析：采取逆向思維的方法，從后往前推斷。<br>
2.程序源代碼：<br>
main()<br>
{<br>
int day,x1,x2;<br>
day=9;<br>
x2=1;<br>
while(day>0)<br>
{x1=(x2+1)*2;/*第一天的桃子數(shù)是第2天桃子數(shù)加1后的2倍*/<br>
x2=x1;<br>
day--;<br>
}<br>
printf("the total is %d\n",x1);<br>
}<br>
==============================================================<br>
<font color="#990000">【程序22】</font><br>
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