?? sphoot.c
字號(hào):
#include <stdio.h>#define NRANSI#include "nrutil.h"#define N2 1int m,n;float c2,dx,gmma;int nvar;float x1,x2;int main(void) /* Program sphoot */{ void newt(float x[], int n, int *check, void (*vecfunc)(int, float [], float [])); void shoot(int n, float v[], float f[]); int check,i; float q1,*v; v=vector(1,N2); dx=1.0e-4; nvar=3; for (;;) { printf("input m,n,c-squared\n"); if (scanf("%d %d %f",&m,&n,&c2) == EOF) break; if (n < m || m < 0) continue; gmma=1.0; q1=n; for (i=1;i<=m;i++) gmma *= -0.5*(n+i)*(q1--/i); v[1]=n*(n+1)-m*(m+1)+c2/2.0; x1 = -1.0+dx; x2=0.0; newt(v,N2,&check,shoot); if (check) { printf("shoot failed; bad initial guess\n"); } else { printf("\tmu(m,n)\n"); printf("%12.6f\n",v[1]); } } free_vector(v,1,N2); return 0;}void load(float x1, float v[], float y[]){ float y1 = (n-m & 1 ? -gmma : gmma); y[3]=v[1]; y[2] = -(y[3]-c2)*y1/(2*(m+1)); y[1]=y1+y[2]*dx;}void score(float xf, float y[], float f[]){ f[1]=(n-m & 1 ? y[1] : y[2]);}void derivs(float x, float y[], float dydx[]){ dydx[1]=y[2]; dydx[2]=(2.0*x*(m+1.0)*y[2]-(y[3]-c2*x*x)*y[1])/(1.0-x*x); dydx[3]=0.0;}#undef N2#undef NRANSI
?? 快捷鍵說(shuō)明
復(fù)制代碼
Ctrl + C
搜索代碼
Ctrl + F
全屏模式
F11
切換主題
Ctrl + Shift + D
顯示快捷鍵
?
增大字號(hào)
Ctrl + =
減小字號(hào)
Ctrl + -