?? bcucof.c
字號(hào):
void bcucof(float y[], float y1[], float y2[], float y12[], float d1, float d2, float **c){ static int wt[16][16]= { 1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, 0,0,0,0,0,0,0,0,1,0,0,0,0,0,0,0, -3,0,0,3,0,0,0,0,-2,0,0,-1,0,0,0,0, 2,0,0,-2,0,0,0,0,1,0,0,1,0,0,0,0, 0,0,0,0,1,0,0,0,0,0,0,0,0,0,0,0, 0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0, 0,0,0,0,-3,0,0,3,0,0,0,0,-2,0,0,-1, 0,0,0,0,2,0,0,-2,0,0,0,0,1,0,0,1, -3,3,0,0,-2,-1,0,0,0,0,0,0,0,0,0,0, 0,0,0,0,0,0,0,0,-3,3,0,0,-2,-1,0,0, 9,-9,9,-9,6,3,-3,-6,6,-6,-3,3,4,2,1,2, -6,6,-6,6,-4,-2,2,4,-3,3,3,-3,-2,-1,-1,-2, 2,-2,0,0,1,1,0,0,0,0,0,0,0,0,0,0, 0,0,0,0,0,0,0,0,2,-2,0,0,1,1,0,0, -6,6,-6,6,-3,-3,3,3,-4,4,2,-2,-2,-2,-1,-1, 4,-4,4,-4,2,2,-2,-2,2,-2,-2,2,1,1,1,1}; int l,k,j,i; float xx,d1d2,cl[16],x[16]; d1d2=d1*d2; for (i=1;i<=4;i++) { x[i-1]=y[i]; x[i+3]=y1[i]*d1; x[i+7]=y2[i]*d2; x[i+11]=y12[i]*d1d2; } for (i=0;i<=15;i++) { xx=0.0; for (k=0;k<=15;k++) xx += wt[i][k]*x[k]; cl[i]=xx; } l=0; for (i=1;i<=4;i++) for (j=1;j<=4;j++) c[i][j]=cl[l++];}?? 快捷鍵說(shuō)明
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