//if_03.cpp
 #include <iostream.h>
 #include <conio.h>
 void main()
 { char fine;
   cout << "天氣晴朗(Y/N)?";
   cin >> fine;
   if (fine=='Y' || fine=='y')		//大小寫的Y/y均可
     cout <<"去郊游!" << endl;
   else
     cout << "去看電影!\n";
   getch();
 }