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?? 一元線性m2.bas

?? 數(shù)理統(tǒng)計(jì)程序集
?? BAS
字號:
Attribute VB_Name = "modMethod"
Option Explicit
'一元線性回歸
'x(1 To n):自變量,n為觀測次數(shù),已知
'y(1 To n):因變量,n為觀測次數(shù),已知
'b0:截距,計(jì)算結(jié)果
'b1:回歸系數(shù),計(jì)算結(jié)果
'F:F檢驗(yàn)值,計(jì)算結(jié)果
't:t檢驗(yàn)值,計(jì)算結(jié)果
Public Sub Linear(x() As Double, y() As Double, b0 As Single, b1 As Single, _
                F As Double, t As Double)
    Dim Xa As Double, Ya As Double, Sxx As Double, Sxy As Double, Syy As Double
    Dim SSR As Double, SSE As Double, Ur As Integer, Ue As Integer
    Dim Syx2 As Double, Sb As Double, Sb2 As Double, Sx As Double
    Dim n As Integer, I As Double
    n = UBound(x, 1)
    For I = 1 To n
        Xa = Xa + x(I): Ya = Ya + y(I)
    Next I
    Xa = Xa / n: Ya = Ya / n                        '平均值
    For I = 1 To n
        Sxx = Sxx + (x(I) - Xa) ^ 2
        Sxy = Sxy + (x(I) - Xa) * (y(I) - Ya)
    Next I
    b1 = Sxy / Sxx                                  '截距
    b0 = Ya - b1 * Xa                               '回歸系數(shù)
'由回歸所導(dǎo)致的方差
    For I = 1 To n
        SSR = SSR + (b0 + b1 * x(I) - Ya) ^ 2
    Next I
    Ur = 1
    SSR = SSR / Ur
'由剩余所導(dǎo)致的方差
    For I = 1 To n
        SSE = SSE + (y(I) - b0 - b1 * x(I)) ^ 2
    Next I
Debug.Print "回歸方差:", SSR, "剩余方差:", SSE
'求F值
    Ue = n - 2
Debug.Print "回歸方差自由度:", Ur, "剩余方差自由度:", Ue
    SSE = SSE / Ue
    F = SSR / SSE
Debug.Print "平均回歸方差:", SSR, "平均剩余方差:", SSE, "F檢驗(yàn)值:", F
'求t值
    For I = 1 To n
        Syx2 = Syx2 + (y(I) - (b0 + b1 * x(I))) ^ 2
    Next I
    Syx2 = Syx2 / (n - 2)
    For I = 1 To n
        Sx = Sx + (x(I) - Xa) ^ 2
    Next I
    Sb2 = Syx2 / Sx: Sb = Sqr(Sb2): t = Abs(b1 / Sb)
End Sub

'求正態(tài)分布的分位數(shù)
'Q:上側(cè)概率
'x:分位數(shù)
Public Sub PNorm(Q, x)
    Dim p As Double, y As Double, z As Double
    Dim b0 As Double, b1 As Double, b2 As Double
    Dim b3 As Double, b4 As Double, b5 As Double
    Dim b6 As Double, b7 As Double, b8 As Double
    Dim b9 As Double, b10 As Double, b As Double
    b0 = 1.570796288: b1 = 0.03706987906
    b2 = -0.0008364353589: b3 = -0.0002250947176
    b4 = 0.000006841218299: b5 = 0.000005824238515
    b6 = -0.00000104527497: b7 = 8.360937017E-08
    b8 = -3.231081277E-09: b9 = 3.657763036E-11
    b10 = 6.936233982E-13
    If Q = 0.5 Then
        x = 0: GoTo PN01
    End If
    If Q > 0.5 Then p = 1 - Q Else p = Q
    y = -Log(4 * p * (1 - p))
    b = y * (b9 + y * b10)
    b = y * (b8 + b): b = y * (b7 + b)
    b = y * (b6 + b): b = y * (b5 + b)
    b = y * (b4 + b): b = y * (b3 + b)
    b = y * (b2 + b): b = y * (b1 + b)
    z = y * (b0 + b): x = Sqr(z)
    If Q > 0.5 Then x = -x
PN01:
End Sub

'計(jì)算F分布的分布函數(shù)
'n1:自由度,已知
'n2:自由度,已知
'F:F值,已知
'p:下側(cè)概率,所求
'd:概率密度,所求
Public Sub F_DIST(n1 As Integer, N2 As Integer, F As Double, _
            p As Double, d As Double)
    Dim x As Double, u As Double, Lu As Double
    Dim IAI As Integer, IBI As Integer, nn1 As Integer, nn2 As Integer
    Dim I As Integer
    Const PI As Double = 3.14159265359
    If F = 0 Then
        p = 0: d = 0: Exit Sub
    End If
    x = n1 * F / (N2 + n1 * F)
    If (n1 \ 2) * 2 = n1 Then
        If (N2 \ 2) * 2 = N2 Then
            u = x * (1 - x): p = x: IAI = 2: IBI = 2
        Else
            u = x * Sqr(1 - x) / 2: p = 1 - Sqr(1 - x): IAI = 2: IBI = 1
        End If
    Else
        If (N2 \ 2) * 2 = N2 Then
            p = Sqr(x): u = p * (1 - x) / 2: IAI = 1: IBI = 2
        Else
            u = Sqr(x * (1 - x)) / PI
            p = 1 - 2 * Atn(Sqr((1 - x) / x)) / PI: IAI = 1: IBI = 1
        End If
    End If
    nn1 = n1 - 2: nn2 = N2 - 2
    If u = 0 Then
        d = u / F
        Exit Sub
    Else
        Lu = Log(u)
    End If
    If IAI = n1 Then GoTo LL1
    For I = IAI To nn1 Step 2
        p = p - 2 * u / I
        Lu = Lu + Log((1 + IBI / I) * x)
        u = Exp(Lu)
    Next I
LL1:
    If IBI = N2 Then
        d = u / F: Exit Sub
    End If
    For I = IBI To nn2 Step 2
        p = p + 2 * u / I
        Lu = Lu + Log((1 + n1 / I) * (1 - x))
        u = Exp(Lu)
    Next I
    d = u / F
End Sub

'計(jì)算F分布的分位數(shù)
'n1:自由度,已知
'n2:自由度,已知
'Q:上側(cè)概率,已知
'F:分位數(shù),所求
Public Sub PF_DIST(n1 As Integer, N2 As Integer, _
                Q As Double, F As Double)
    Dim DF12 As Double, DF22 As Double, A As Double, b As Double
    Dim A1 As Double, b1 As Double, p As Double, YQ As Double
    Dim E As Double, FO As Double, pp As Double, d As Double
    Dim GA1 As Double, GA2 As Double, GA3 As Double
    Dim K As Integer
    DF12 = n1 / 2: DF22 = N2 / 2
    A = 2 / (9 * n1): A1 = 1 - A
    b = 2 / (9 * N2): b1 = 1 - b
    p = 1 - Q: PNorm Q, YQ
    E = b1 * b1 - b * YQ * YQ
    If E > 0.8 Then
        FO = ((A1 * b1 + YQ * Sqr(A1 * A1 * b + A * E)) / E) ^ 3
    Else
        lnGamma DF12 + DF22, GA1
        lnGamma DF12, GA2
        lnGamma DF22, GA3
        FO = (2 / N2) * (GA1 - GA2 - GA3 + 0.69315 + (DF22 - 1) * Log(N2) _
            - DF22 * Log(n1) - Log(Q))
        FO = Exp(FO)
    End If
    For K = 1 To 30
        F_DIST n1, N2, FO, pp, d
        If d = 0 Then
            F = FO: Exit Sub
        End If
        F = FO - (pp - p) / d
        If Abs(FO - F) < 0.000001 * Abs(F) Then Exit Sub Else FO = F
    Next K
End Sub

'計(jì)算GAMMA函數(shù)
'x:自變量
'z:GAMMA函數(shù)值
Public Sub GAMMA(x As Double, z As Double)
    Dim H As Double, y As Double, y1 As Double
    H = 1: y = x
LL1:
    If y = 2 Then
        z = H
        Exit Sub
    ElseIf y < 2 Then
        H = H / y: y = y + 1: GoTo LL1
    ElseIf y >= 3 Then
        y = y - 1: H = H * y: GoTo LL1
    End If
    y = y - 2
    y1 = y * (0.005159 + y * 0.001606)
    y1 = y * (0.004451 + y1)
    y1 = y * (0.07211 + y1)
    y1 = y * (0.082112 + y1)
    y1 = y * (0.41174 + y1)
    y1 = y * (0.422787 + y1)
    H = H * (0.999999 + y1)
    z = H
End Sub

'求Gamma函數(shù)的對數(shù)LogGamma(x)
'x:自變量
'G:Gamma函數(shù)的對數(shù)
Public Sub lnGamma(x As Double, G As Double)
    Dim y As Double, z As Double, A As Double
    Dim b As Double, b1 As Double, n As Integer
    Dim I As Integer
    If x < 8 Then
        y = x + 8: n = -1
    Else
        y = x: n = 1
    End If
    z = 1 / (y * y)
    A = (y - 0.5) * Log(y) - y + 0.9189385
    b1 = (0.0007663452 * z - 0.0005940956) * z
    b1 = (b1 + 0.0007936431) * z
    b1 = (b1 - 0.002777778) * z
    b = (b1 + 0.0833333) / y
    G = A + b
    If n >= 0 Then Exit Sub
    y = y - 1: A = y
    For I = 1 To 7
        A = A * (y - I)
    Next I
    G = G - Log(A)
End Sub

'計(jì)算t分布的分布函數(shù)
'n:自由度,已知
'T:t值,已知
'pp:下側(cè)概率,所求
'dd:概率密度,所求
Public Sub T_Dist(n As Integer, t As Double, pp As Double, dd As Double)
    Dim Sign As Integer, TT As Double, x As Double
    Dim p As Double, u As Double, GA1 As Double, GA2 As Double
    Dim IBI As Integer, N2 As Integer, I As Integer
    Const PI As Double = 3.14159265359
    If t = 0 Then
        Call GAMMA(n / 2, GA1): Call GAMMA(n / 2 + 0.5, GA2): pp = 0.5
        dd = GA2 / (Sqr(n * PI) * GA1): Exit Sub
    End If
    If t < 0 Then Sign = -1 Else Sign = 1
    TT = t * t: x = TT / (n + TT)
    If (n \ 2) * 2 = n Then                 'n為偶數(shù)
        p = Sqr(x): u = p * (1 - x) / 2
        IBI = 2
    Else                                    'n為奇數(shù)
        u = Sqr(x * (1 - x)) / PI
        p = 1 - 2 * Atn(Sqr((1 - x) / x)) / PI
        IBI = 1
    End If
    If IBI = n Then GoTo LL1 Else N2 = n - 2
    For I = IBI To N2 Step 2
        p = p + 2 * u / I
        u = u * (1 + I) / I * (1 - x)
    Next I
LL1:
    dd = u / Abs(t)
    pp = 0.5 + Sign * p / 2
End Sub

'求t分布的分位數(shù)
'n:自由度,已知
'Q:上側(cè)概率(<=0.5),已知
'T:分位數(shù),所求
Public Sub PT_DIST(n As Integer, Q As Double, t As Double)
    Dim PIS As Double, DFR2 As Double, C As Double
    Dim Q2 As Double, p As Double, YQ As Double, E As Double
    Dim GA1 As Double, GA2 As Double, GA3 As Double
    Dim T0 As Double, pp As Double, d As Double
    Dim K As Integer
    Const PI As Double = 3.14159265359
    PIS = Sqr(PI): DFR2 = n / 2
    If n = 1 Then
        t = Tan(PI * (0.5 - Q)): Exit Sub
    End If
    If n = 2 Then
        If Q > 0.5 Then C = -1 Else C = 1
        Q2 = (1 - 2 * Q) ^ 2
        t = Sqr(2 * Q2 / (1 - Q2)) * C
        Exit Sub
    End If
    p = 1 - Q: PNorm Q, YQ              '正態(tài)分布分位數(shù)
    E = (1 - 1 / (4 * n)) ^ 2 - YQ * YQ / (2 * n)
    If E > 0.5 Then
        T0 = YQ / Sqr(E)
    Else
        lnGamma DFR2, GA1: lnGamma DFR2 + 0.5, GA2
        GA3 = Exp((GA1 - GA2) / n)
        T0 = Sqr(n) / (PIS * Q * n) ^ (1 / n) / GA3
    End If
    For K = 1 To 30
        T_Dist n, T0, pp, d
        If d = 0 Then
            t = T0: Exit Sub
        End If
        t = T0 - (pp - p) / d
        If Abs(T0 - t) < 0.000001 * Abs(t) Then _
            Exit Sub Else T0 = t
    Next K
End Sub







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