電腦出題人來做C語言模擬[原創] 
程序運行效果：計算機隨即產生一個四位數，然后讓人來猜，并且每次提示猜對的位數，直到用戶猜對為止。如某次運行結果如下，計算機隨即產生5130，我猜的過程如下：

Guess what number I have thought of:4567

I am sorry.You are wrong.Only 0 digits are right.Try another one.1234

I am sorry.You are wrong.Only 1 digits are right.Try another one.1235

I am sorry.You are wrong.Only 1 digits are right.Try another one.1432

I am sorry.You are wrong.Only 1 digits are right.Try another one.1345

I am sorry.You are wrong.Only 0 digits are right.Try another one.1234

I am sorry.You are wrong.Only 1 digits are right.Try another one.2431

I am sorry.You are wrong.Only 1 digits are right.Try another one.2234

I am sorry.You are wrong.Only 1 digits are right.Try another one.3234

I am sorry.You are wrong.Only 1 digits are right.Try another one.4231

I am sorry.You are wrong.Only 1 digits are right.Try another one.5231

I am sorry.You are wrong.Only 2 digits are right.Try another one.5131

I am sorry.You are wrong.Only 3 digits are right.Try another one.5132

I am sorry.You are wrong.Only 3 digits are right.Try another one.5133

I am sorry.You are wrong.Only 3 digits are right.Try another one.5134

I am sorry.You are wrong.Only 3 digits are right.Try another one.5135

I am sorry.You are wrong.Only 3 digits are right.Try another one.5136

I am sorry.You are wrong.Only 3 digits are right.Try another one.5137

I am sorry.You are wrong.Only 3 digits are right.Try another one.5138

I am sorry.You are wrong.Only 3 digits are right.Try another one.5139

I am sorry.You are wrong.Only 3 digits are right.Try another one.5130

Great!You are right.The number I have thought of is:5130

好了，代碼是這樣的：

/*
   程序功能：計算機隨機產生一個數，人來猜，計算機提示猜對的位數
   作者：BugEyes
   主頁：http://bugeyes.blog.edu.cn
*/

＃i nclude <stdlib.h>
＃i nclude <time.h>

void main()
{
   int pc,pc_array[4];
   int user,user_array[4];
   int i,count;
   int t;
   srand(time(NULL));/*種子*/
   pc=(random(9)+1)*1000+random(1000);/*產生隨機數*/
   t=pc;
   for(i=0;i<4;i++)/*把隨機數放入數組以便判斷*/
   {
      pc_array[i]=t%10;
      t=t/10;
   }
   printf("\nGuess what number I have thought of:");
   scanf("%d",&user);
   while(user<1000||user>9999)/*保證用戶猜的數為4位*/
   {
      printf("\nPlease input a 4-digit number:");
      scanf("%d",&user);
   }
   for(i=0;i<4;i++)/*把用戶猜的4位數放入數組以便判斷*/
   {
      user_array[i]=user%10;
      user=user/10;
   }
   do
   {
      count=0;/*恢復*/
      for(i=0;i<4;i++)
          if(pc_array[i]==user_array[i])
               count++;/*猜對的位數*/
      if(count==4)/*猜對了*/
      {
           printf("\nGreat!You are right.The number I have thought of is:%d",pc);
           return;/*結束程序*/
      }
      printf("\nI am sorry.You are wrong.Only %d digits are right.Try another one.",count);/*提示用戶猜對的位數*/
      scanf("%d",&user);
      while(user<1000||user>9999)
      {
          printf("\nPlease input a 4-digit number:");
          scanf("%d",&user);
      }
      for(i=0;i<4;i++)
      {
         user_array[i]=user%10;
         user=user/10;
      }
   }while(count<4);/*用戶沒有猜對，繼續猜*/
}