?? simp3.c
字號:
void simp3(float **a, int i1, int k1, int ip, int kp)
{
int kk,ii;
float piv;
piv=1.0/a[ip+1][kp+1];
for (ii=1;ii<=i1+1;ii++)
if (ii-1 != ip) {
a[ii][kp+1] *= piv;
for (kk=1;kk<=k1+1;kk++)
if (kk-1 != kp)
a[ii][kk] -= a[ip+1][kk]*a[ii][kp+1];
}
for (kk=1;kk<=k1+1;kk++)
if (kk-1 != kp) a[ip+1][kk] *= -piv;
a[ip+1][kp+1]=piv;
}
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