%計算適應值

% function [adapt,ada_ave]=adapting(pop)

for i=1:40
    adapt(i)=0;
end

for i=1:40
    for j=1:10
        if pop(i,j)==1
            adapt(i)=adapt(i)+2^(10-j);
        end
    end
    adapt(i)=adapt(i)*0.0029;
    adapt(i)=-(adapt(i)-1).^2+4;
end

adapt_best=0;
adapt_ave=0;

for i=1:40
    adapt_ave=adapt_ave+adapt(i);
    if adapt_
end

adapt_ave=adapt_ave/40;


clear i;
clear j;