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<P><FONT color=#ff9933><B><FONT size=5> <FONT
color=#3300cc>經典c程序100例==21--30</FONT></FONT></B></FONT></P>
<P><FONT
color=#990000>【程序21】</FONT><BR>題目：猴子吃桃問題：猴子第一天摘下若干個桃子，當即吃了一半，還不癮，又多吃了一個<BR> 第二天早上又將剩下的桃子吃掉一半，又多吃了一個。以后每天早上都吃了前一天剩下<BR> 的一半零一個。到第10天早上想再吃時，見只剩下一個桃子了。求第一天共摘了多少。<BR>1.程序分析：采取逆向思維的方法，從后往前推斷。<BR>2.程序源代碼：<BR>main()<BR>{<BR>int
day,x1,x2;<BR>day=9;<BR>x2=1;<BR>while(day>0)<BR> {x1=(x2+1)*2;/*第一天的桃子數是第2天桃子數加1后的2倍*/<BR> x2=x1;<BR> day--;<BR> }<BR>printf("the
total is
%d\n",x1);<BR>}<BR>==============================================================<BR><FONT
color=#990000>【程序22】</FONT><BR>題目：兩個乒乓球隊進行比賽，各出三人。甲隊為a,b,c三人，乙隊為x,y,z三人。已抽簽決定<BR> 比賽名單。有人向隊員打聽比賽的名單。a說他不和x比，c說他不和x,z比，請編程序找出<BR> 三隊賽手的名單。
<BR>1.程序分析：判斷素數的方法：用一個數分別去除2到sqrt(這個數)，如果能被整除，<BR> 則表明此數不是素數，反之是素數。
<BR>2.程序源代碼：<BR>main()<BR>{<BR>char
i,j,k;/*i是a的對手，j是b的對手，k是c的對手*/<BR>for(i='x';i<='z';i++)<BR> for(j='x';j<='z';j++)<BR> {<BR> if(i!=j)<BR> for(k='x';k<='z';k++)<BR> {
if(i!=k&&j!=k)<BR> {
if(i!='x'&&k!='x'&&k!='z')<BR> printf("order
is
a--%c\tb--%c\tc--%c\n",i,j,k);<BR> }<BR> }<BR> }<BR>}<BR>==============================================================<BR><FONT
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