?? 位置式pid控制算法.m
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%PID Controller,位置式PID控制算法,u(k)對應執行機構的實際位置
clear all;
close all;
ts=0.001;
sys=tf(5.235e005,[1,87.35,1.047e004,0]); %transfer function (TF)
dsys=c2d(sys,ts,'zoh');%Convert a model from continuous time to discrete time
%Index里沒有,在Search里找
[num,den]=tfdata(dsys,'v');%Quick access to transfer function data
u_1=0.0;u_2=0.0;u_3=0.0;
y_1=0.0;y_2=0.0;y_3=0.0;
x=[0,0,0]';
error_1=0;
for k=1:1:1500
time(k)=k*ts;
S=1;
if S==1
kp=0.50;ki=0.001;kd=0.001;
rin(k)=1; %Step Signal
elseif S==2
kp=0.50;ki=0.001;kd=0.001;
rin(k)=sign(sin(2*2*pi*k*ts)); %Square Wave Signal
elseif S==3
kp=1.5;ki=1.0;kd=0.01; %Sine Signal
rin(k)=0.5*sin(2*2*pi*k*ts);
end
u(k)=kp*x(1)+kd*x(2)+ki*x(3); %PID Controller
%Restricting the output of controller
if u(k)>=10
u(k)=10;
end
if u(k)<=-10
u(k)=-10;
end
%Linear model
yout(k)=-den(2)*y_1-den(3)*y_2-den(4)*y_3+num(2)*u_1+num(3)*u_2+num(4)*u_3;%差分方程,迭代解法,(while微分方程是ode)
error(k)=rin(k)-yout(k);
%Return of parameters
u_3=u_2;u_2=u_1;u_1=u(k);
y_3=y_2;y_2=y_1;y_1=yout(k);
x(1)=error(k); %Calculating P
x(2)=(error(k)-error_1)/ts; %Calculating D
x(3)=x(3)+error(k)*ts; %Calculating I
error_1=error(k);
end
figure(1);
plot(time,rin,'k',time,yout,'k');
xlabel('time(s)'),ylabel('rin,yout');
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