?? root.m
字號:
function uid = root(tree)
% XMLTREE/ROOT Root Method
% FORMAT uid = root(tree)
%
% tree - XMLTree object
% uid - UID of the root element of tree
%_______________________________________________________________________
%
% Return the uid of the root element of the tree.
%_______________________________________________________________________
% @(#)root.m Guillaume Flandin 02/04/17
% Actually root is necessarily the element whos UID is 1, by
% construction. However, xml_parser should return a tree with a ROOT
% element with as many children as needed but only ONE *element* child
% who would be the real root (and this method should return the UID of
% this element).
uid = 1;
% Update:
% xml_parser has been modified (not as explained above) to handle the
% case when several nodes are at the top level of the XML.
% Example: <!-- beginning --><root>blah blah</root><!-- end -->
% Now root is the first element node of the tree.
% Look for the first element in the XML Tree
for i=1:length(tree)
if strcmp(get(tree,i,'type'),'element')
uid = i;
break
end
end
?? 快捷鍵說明
復制代碼
Ctrl + C
搜索代碼
Ctrl + F
全屏模式
F11
切換主題
Ctrl + Shift + D
顯示快捷鍵
?
增大字號
Ctrl + =
減小字號
Ctrl + -