?? glmerr.m
字號(hào):
function [e, y, a, edata, eprior] = glmerr(net, x, t)%GLMERR Evaluate error function for generalized linear model.%% Description% E = GLMERR(NET, X, T) takes a generalized linear model data% structure NET together with a matrix X of input vectors and a matrix% T of target vectors, and evaluates the error function E. The choice% of error function corresponds to the output unit activation function.% Each row of X corresponds to one input vector and each row of T% corresponds to one target vector.%% [E, Y, A] = GLMERR(NET, X) also returns a matrix Y giving the outputs% of the models and a matrix A giving the summed inputs to each output% unit, where each row corresponds to one pattern.%% [E, Y, A, EDATA, EPRIOR] = GLMERR(NET, X, T) also returns the data% and prior components of the total error.%% See also% GLM, GLMPAK, GLMUNPAK, GLMFWD, GLMGRAD, GLMTRAIN%% Copyright (c) Christopher M Bishop, Ian T Nabney (1996, 1997)% Check arguments for consistencyerrstring = consist(net, 'glm', x, t);if ~isempty(errstring); error(errstring);end[y, a] = glmfwd(net, x);switch net.actfn case 'linear' % Linear outputs e = 0.5*sum(sum((y - t).^2)); case 'logistic' % Logistic outputs % Ensure that log(1-y) is computable: need exp(a) > eps maxcut = -log(eps); % Ensure that log(y) is computable mincut = -log(1/realmin - 1); a = min(a, maxcut); a = max(a, mincut); y = 1./(1 + exp(-a)); e = - sum(sum(t.*log(y) + (1 - t).*log(1 - y))); case 'softmax' % Softmax outputs nout = size(a,2); % Ensure that sum(exp(a), 2) does not overflow maxcut = log(realmax) - log(nout); % Ensure that exp(a) > 0 mincut = log(realmin); a = min(a, maxcut); a = max(a, mincut); temp = exp(a); y = temp./(sum(temp, 2)*ones(1,nout)); % Ensure that log(y) is computable y(y<realmin) = realmin; e = - sum(sum(t.*log(y)));endif isfield(net, 'beta') e1 = net.beta*e;else e1 = e;endif isfield(net, 'alpha') w = glmpak(net); if size(net.alpha) == [1 1] eprior = 0.5*(w*w'); e2 = eprior*net.alpha; else eprior = 0.5*(w.^2)*net.index; e2 = eprior*net.alpha; endelse eprior = 0; e2 = 0;ende = e1 + e2;
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