?? 林志貴.m
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% 基于修改模型的沖突證據(jù)組合方法,林志貴,上 海 交 通 大 學學報
clear;clc;
% m1A = 0.98; m1B=0.01; m1C=0.01;
% m2A = 0 ; m2B=0.01; m2C=0.99;
% m3A = 0.9; m3B=0; m3C=0.1;
m1A = 0.5; m1B=0.2; m1C=0.3;
m2A = 0 ; m2B=0.9; m2C=0.1;
m3A = 0.55; m3B=0.1; m3C=0.35;
%mass 函數(shù)之間的距離
innerProdm1 = m1A^2+m1B^2+m1C^2;
innerProdm2 = m2A^2+m2B^2+m2C^2;
innerProdm3 = m3A^2+m3B^2+m3C^2;
innerProdm12 = m1A*m2A+m1B*m2B+m1C*m2C;
innerProdm13 = m1A*m3A+m1B*m3B+m1C*m3C;
innerProdm23 = m2A*m3A+m2B*m3B+m2C*m3C;
dm12 =(0.5*(innerProdm1+innerProdm2-2*innerProdm12))^0.5;
dm13 =(0.5*(innerProdm1+innerProdm3-2*innerProdm13))^0.5;
dm23 =(0.5*(innerProdm2+innerProdm3-2*innerProdm23))^0.5;
%證據(jù)之間的相似度
Simm12 = 1 - dm12;
Simm13 = 1 - dm13;
Simm23 = 1 - dm23;
%證據(jù)的支持度
Supm1 = Simm12+Simm13;
Supm2 = Simm12+Simm23;
Supm3 = Simm13+Simm23;
%證據(jù)的可信度
Crdm1 = Supm1/(Supm1+Supm2+Supm3);
Crdm2 = Supm2/(Supm1+Supm2+Supm3);
Crdm3 = Supm3/(Supm1+Supm2+Supm3);
%得出可信度后,可以用可信度作為權重修改證據(jù)的可信度
m1A = m1A * Crdm1;m1B = m1B * Crdm1;m1C = m1C * Crdm1;
m2A = m2A * Crdm2;m2B = m2B * Crdm2;m2C = m2C * Crdm2;
m3A = m3A * Crdm3;m3B = m3B * Crdm3;m3C = m3C * Crdm3;
%為了避免一票否決現(xiàn)象,進行平均融合
m1A = (m1A+m2A+m3A)/3; m2A = m1A; m3A = m1A;
m1B = (m1B+m2B+m3B)/3; m2B = m1B; m3B = m1B;
m1C = (m1C+m2C+m3C)/3; m2C = m1C; m3C = m1C;
%融合結果
m1A = m1A^3;
m1B = m1B^3;
m1C = m1C^3;
mA =m1A/(m1A+m1B+m1C);
mB =m1B/(m1A+m1B+m1C);
mC =m1C/(m1A+m1B+m1C);
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