/*
 * 示例程序Sample6_13: Interpolation類的第一種邊界條件的三次樣條函數插值、微商與積分
 */

using System;
using CSharpAlgorithm.Algorithm;

namespace CSharpAlgorithm.Sample
{
	class Class1
	{
		[STAThread]
		static void Main(string[] args)
		{
            // 數據
            int n = 12;
            double[] x = {0.52,8.0,17.95,28.65,50.65,104.6,156.6,260.7,364.4,468.0,507.0,520.0};
            double[] y = {5.28794,13.84,20.2,24.9,31.1,36.5,36.6,31.0,20.9,7.8,1.5,0.2};
            double[] t = {4.0,14.0,30.0,60.0,130.0,230.0,450.0,515.0};
		
            // 微分
            double[] dy = new double[n];
            double[] ddy = new double[n];
            dy[0] = 1.86548;
            dy[n-1] = -0.046115;

            // 插值運算
            int m = 8;
            double[] z = new double[m];
            double[] dz = new double[m];
            double[] ddz = new double[m];
		
            double yt = Interpolation.GetValueSpline1(n, x, y, dy, ddy, m, t, z, dz, ddz);
            Console.WriteLine("定積分值 = " + yt);
            Console.WriteLine("\nt[i]\t\tz[i]\t\t\tdz[i]\t\t\tddz[i]\n");
            for (int i=0; i<m; ++i)
            {
                Console.WriteLine(t[i] + "\t" + z[i] + "\t" + dz[i] + "\t" + ddz[i]);
            }		
        }
	}
}