function [x,iflaw]=fmpower(N,k,p1,p2)%FMPOWER Signal with power-law frequency modulation.%	[X,IFLAW]=FMPOWER(N,K,P1,P2) generates a signal with a%	power-law frequency modulation.%	X(t) = exp(j*2*pi(F0*t + C/(1-K)*abs(t).^(1-K))) %%	N  : number of points in time%	K  : degree of the power-law (K~=1)%	P1 : if the number of input arguments (NARGIN) is 3, P1 is a %	    vector containing the two coefficients [F0 C] for a%	    power-law instantaneous frequency (sampling frequency is set to 1).%	    If NARGIN=4, P1 (as P2) is a time-frequency point of the %	    form [Ti Fi]. Ti is in seconds and Fi is a normalized frequency%	    (between 0 and 0.5). The coefficients F0 %	    and C are then deduced such that the frequency modulation %	    law fits the points P1 and P2.%	P2 : same as P1 if NARGIN=4         (optional)%	X  : time row vector containing the modulated signal samples%	IFLAW : instantaneous frequency law%%	Examples :   %	 [X,IFLAW]=fmpower(128,0.5,[1 0.5],[100 0.1]);%	 subplot(211);plot(real(X));subplot(212);plot(IFLAW);%%	See also GDPOWER, FMCONST, FMLIN, FMHYP, FMPAR, FMODANY, FMSIN.%	P. Goncalves - October 1995, O. Lemoine - April 1996.%	Copyright (c) 1995 Rice University, 1996 CNRS (France).%%	------------------- CONFIDENTIAL PROGRAM -------------------- %	This program can not be used without the authorization of its%	author(s). For any comment or bug report, please send e-mail to %	f.auger@ieee.org if (nargin <= 2), error ( 'The number of parameters must be at least 3.' );elseif (N <= 0), error ('The signal length N must be strictly positive' );elseif abs(k-1)<sqrt(eps),  error('K must be different from 1');elseif nargin == 3  if length(p1) ~= 2   error('Bad number of coefficients');  end  f0 = p1(1) ; c = p1(2) ;elseif nargin == 4 ;  if (length(p1) ~= 2) |(length(p2) ~= 2),   error('Bad number of coefficients for P1 or P2');  end  if p1(1)>N | p1(1)<1,   error ('P1(1) must be between 1 and N');  elseif p2(1)>N | p2(1)<1,   error ('P2(1) must be between 1 and N');  elseif p1(2)<0,   error ('P1(2) must be > 0');  elseif p2(2)<0,   error ('P2(2) must be > 0');  end  c  = (p2(2) - p1(2))/(1/p2(1)^k - 1/p1(1)^k) ;  f0 = p1(2) - c/p1(1)^k ;end  t=1:N;phi = 2*pi*(f0*t + c/(1-k)*abs(t).^(1-k)) ;iflaw = (f0 + c*abs(t).^(-k)).' ;aliasing = find(iflaw<0 | iflaw>0.5) ;if isempty(aliasing) == 0  disp(['!!! WARNING: signal is undersampled or has negative frequencies']) ;endx = exp(i*phi).';