/*==================================================
  由于每次鍵盤(pán)上電或復(fù)位后都會(huì)自檢，然后發(fā)出0xAA到PC
  若每次采集33次中斷數(shù)據(jù)則會(huì)出現(xiàn)一點(diǎn)小問(wèn)題，我的解決
  辦法是只利用收集到的中間11位數(shù)據(jù)
  =================================================*/
#include<reg51.h>

#define uchar unsigned char

sbit Clk=P3^2;                  //時(shí)鐘線接在P32
sbit Dat=P1^0;                  //數(shù)據(jù)線接在P10

uchar Degree=0;
uchar Data=0;

void Get_data(void) interrupt 0 using 1
{
 if((Degree>11)&&(Degree<20))
 	{
		Data=Data>>1;
	 	if(Dat){Data|=0x80;};		
	}                                          //只用采集到的中間11位的八位數(shù)據(jù)

 Degree++;
 if(Degree>=33)
	{Degree=0;
	 P2=Data;
	 }             //32次后重新計(jì)數(shù)
}


void main(void)
{
 IT0=1;
 EA=1;
 EX0=1;
 while(1); 

}