// 3.下面是一個(gè)結(jié)構(gòu)聲明:
// struct chaff
// {
// 	 char dross[20];
// 	 int slag;
// };
// 編寫一個(gè)程序,使用布局new操作符將一個(gè)包含兩個(gè)這種結(jié)構(gòu)的數(shù)組放在一個(gè)緩沖
// 區(qū)中.然后,給結(jié)構(gòu)的成員賦值(對(duì)于char數(shù)組,使用strcpy() ),并使用一個(gè)循環(huán)來
// 顯示內(nèi)容.方法1是像程序清單9.9那樣將一個(gè)靜態(tài)數(shù)組用作緩沖區(qū);方法2是使用常
// new操作符來分配緩沖區(qū)

#include <iostream>
#include <cstring>
#include <new>			// for placement new
const int BUF = 1000;
const int N =2;

struct chaff
{
	char dross[20];
	int slag;
};

int main()
{
	using namespace std;
	char buffer[BUF];
	chaff * p1 = new chaff[N];			// use heap
	chaff * p2 = new (buffer) chaff[N];	// use buffer array
	for(int i = 0; i<N; i++)
	{
		cout<<"Please input the dross"<<i+1<<": ";
		char temp[20];
		cin.get(temp,20);
		 while(cin.get() != '\n')    // 截掉多余字符
			   continue;
		strcpy(p1[i].dross,temp);
		strcpy(p2[i].dross,temp);
		cout<<"Please input the slag"<<i+1<<": ";
		cin>>p1[i].slag;
		while(!cin)			// if bad input,input again
		{
			cin.clear();
		    while(cin.get() != '\n')    // 截掉多余字符
			   continue;
			cout<<"Please a integer for slag"<<i+1<<": ";
			cin>>p1[i].slag;
		}
		cin.get();
        p2[i].slag = p1[i].slag;
	}
	cout<<"Buffer addresses:\n"<<" heap: "<<p1
		<<" static: "<<(void *) buffer <<endl;
	for(int j = 0; j<N; j++)
	{
		cout<<p1[i].dross<<"->"<<p1[i].slag<<" at "<<&p1[i];
		cout<<p2[i].dross<<"->"<<p2[i].slag<<" at "<<&p2[i]<<endl;
	}
	return 0;
}