?? testfinal.m
字號(hào):
clear,close all
load('E:\matlab2006\work\H.mat')
Hqc(1:1397,1:7493)=H
br=127
[cb,tb]=size(Hqc)
D=Hqc(1:cb,tb-cb+1:tb)
Hqc1=gauss(Hqc)
D1=gauss(D)
rd=rank(D1)
r= rank(Hqc1)
if r==cb
delta_r=r-rd
switch delta_r
case 0
D=[D,eye(cb)]
D=gauss(D)
invD=D(1:cb,cb+1:2*cb)%求得D的逆陣
M=Hqc(1:cb,1:tb-cb)
TEM=mod(invD*M,2)
I=eye(tb-cb)
Z=mod(TEM*I,2)
P=conj(Z)'
Gqc=[I,P]
otherwise %如果Hqc滿(mǎn)秩D非滿(mǎn)秩,則將Hqc序列重排
tmp=Hqc(1:cb,tb-delta_r+1:tb)
Hqc(1:cb,1+delta_r:tb)=Hqc(1:cb,1:tb-delta_r)
Hqc(1:cb,1:delta_r)=tmp
per_D=Hqc(1:cb,tb-cb+1:tb)
per_D1=gauss(per_D)
delta_l=0
%如果D仍然非滿(mǎn)秩,則增加列數(shù)
while (r-rank(per_D1))>0
delta_l=delta_l+1
per_D=Hqc(1:cb,tb-cb+1-delta_l*br:tb)
per_D1=per_D,end
lb=delta_l*br+cb, %得到新的列數(shù)
end
else
delta_r=r-rd
switch delta_r
case 0
per_D=D1
per_D1=gauss(per_D(1:rank(Hqc1),1:cb))
Q=[per_D1;per_D(cb-rank(Hqc1)+1:cb,1:cb)]
Q=Q(1:cb,cb-rank(Hqc1)+1:cb)
otherwise
tmp=Hqc(1:cb,tb-delta_r+1:tb)
Hqc(1:cb,1+delta_r:tb)=Hqc(1:cb,1:tb-delta_r)
Hqc(1:cb,1:delta_r)=tmp
per_D=Hqc(1:cb,tb-cb+1:tb)
per_D1=gauss(per_D)
delta_l=0
while (r-rank(per_D1))>0
delta_l=delta_l+1
per_D=Hqc(1:cb,tb-cb+1-delta_l*br:tb)
per_D1=per_D,end
lb=delta_l*br+cb, %得到新的列數(shù)
end
per_D2=gauss(per_D1(1:r,1:cb))
w=[per_D2;per_D1(r+1:cb,1:cb)]
q=w(1:cb,r+1:cb)
end
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