?? ieee754-sf.s
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/* ieee754-sf.S single-precision floating point support for ARM Copyright (C) 2003, 2004 Free Software Foundation, Inc. Contributed by Nicolas Pitre (nico@cam.org) This file is free software; you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation; either version 2, or (at your option) any later version. In addition to the permissions in the GNU General Public License, the Free Software Foundation gives you unlimited permission to link the compiled version of this file into combinations with other programs, and to distribute those combinations without any restriction coming from the use of this file. (The General Public License restrictions do apply in other respects; for example, they cover modification of the file, and distribution when not linked into a combine executable.) This file is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License for more details. You should have received a copy of the GNU General Public License along with this program; see the file COPYING. If not, write to the Free Software Foundation, 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA. *//* * Notes: * * The goal of this code is to be as fast as possible. This is * not meant to be easy to understand for the casual reader. * * Only the default rounding mode is intended for best performances. * Exceptions aren't supported yet, but that can be added quite easily * if necessary without impacting performances. */#ifdef L_negsf2 ARM_FUNC_START negsf2 eor r0, r0, #0x80000000 @ flip sign bit RET FUNC_END negsf2#endif#ifdef L_addsubsf3ARM_FUNC_START subsf3 eor r1, r1, #0x80000000 @ flip sign bit of second arg#if defined(__thumb__) && !defined(__THUMB_INTERWORK__) b 1f @ Skip Thumb-code prologue#endifARM_FUNC_START addsf31: @ Compare both args, return zero if equal but the sign. eor r2, r0, r1 teq r2, #0x80000000 beq LSYM(Lad_z) @ If first arg is 0 or -0, return second arg. @ If second arg is 0 or -0, return first arg. bics r2, r0, #0x80000000 moveq r0, r1 bicnes r2, r1, #0x80000000 RETc(eq) @ Mask out exponents. mov ip, #0xff000000 and r2, r0, ip, lsr #1 and r3, r1, ip, lsr #1 @ If either of them is 255, result will be INF or NAN teq r2, ip, lsr #1 teqne r3, ip, lsr #1 beq LSYM(Lad_i) @ Compute exponent difference. Make largest exponent in r2, @ corresponding arg in r0, and positive exponent difference in r3. subs r3, r3, r2 addgt r2, r2, r3 eorgt r1, r0, r1 eorgt r0, r1, r0 eorgt r1, r0, r1 rsblt r3, r3, #0 @ If exponent difference is too large, return largest argument @ already in r0. We need up to 25 bit to handle proper rounding @ of 0x1p25 - 1.1. cmp r3, #(25 << 23) RETc(hi) @ Convert mantissa to signed integer. tst r0, #0x80000000 orr r0, r0, #0x00800000 bic r0, r0, #0xff000000 rsbne r0, r0, #0 tst r1, #0x80000000 orr r1, r1, #0x00800000 bic r1, r1, #0xff000000 rsbne r1, r1, #0 @ If exponent == difference, one or both args were denormalized. @ Since this is not common case, rescale them off line. teq r2, r3 beq LSYM(Lad_d)LSYM(Lad_x): @ Scale down second arg with exponent difference. @ Apply shift one bit left to first arg and the rest to second arg @ to simplify things later, but only if exponent does not become 0. movs r3, r3, lsr #23 teqne r2, #(1 << 23) movne r0, r0, lsl #1 subne r2, r2, #(1 << 23) subne r3, r3, #1 @ Shift second arg into ip, keep leftover bits into r1. mov ip, r1, asr r3 rsb r3, r3, #32 mov r1, r1, lsl r3 add r0, r0, ip @ the actual addition @ We now have a 64 bit result in r0-r1. @ Keep absolute value in r0-r1, sign in r3. ands r3, r0, #0x80000000 bpl LSYM(Lad_p) rsbs r1, r1, #0 rsc r0, r0, #0 @ Determine how to normalize the result.LSYM(Lad_p): cmp r0, #0x00800000 bcc LSYM(Lad_l) cmp r0, #0x01000000 bcc LSYM(Lad_r0) cmp r0, #0x02000000 bcc LSYM(Lad_r1) @ Result needs to be shifted right. movs r0, r0, lsr #1 mov r1, r1, rrx add r2, r2, #(1 << 23)LSYM(Lad_r1): movs r0, r0, lsr #1 mov r1, r1, rrx add r2, r2, #(1 << 23) @ Our result is now properly aligned into r0, remaining bits in r1. @ Round with MSB of r1. If halfway between two numbers, round towards @ LSB of r0 = 0. LSYM(Lad_r0): add r0, r0, r1, lsr #31 teq r1, #0x80000000 biceq r0, r0, #1 @ Rounding may have added a new MSB. Adjust exponent. @ That MSB will be cleared when exponent is merged below. tst r0, #0x01000000 addne r2, r2, #(1 << 23) @ Make sure we did not bust our exponent. cmp r2, #(254 << 23) bhi LSYM(Lad_o) @ Pack final result together.LSYM(Lad_e): bic r0, r0, #0x01800000 orr r0, r0, r2 orr r0, r0, r3 RET @ Result must be shifted left. @ No rounding necessary since r1 will always be 0.LSYM(Lad_l):#if __ARM_ARCH__ < 5 movs ip, r0, lsr #12 moveq r0, r0, lsl #12 subeq r2, r2, #(12 << 23) tst r0, #0x00ff0000 moveq r0, r0, lsl #8 subeq r2, r2, #(8 << 23) tst r0, #0x00f00000 moveq r0, r0, lsl #4 subeq r2, r2, #(4 << 23) tst r0, #0x00c00000 moveq r0, r0, lsl #2 subeq r2, r2, #(2 << 23) tst r0, #0x00800000 moveq r0, r0, lsl #1 subeq r2, r2, #(1 << 23) cmp r2, #0 bgt LSYM(Lad_e)#else clz ip, r0 sub ip, ip, #8 mov r0, r0, lsl ip subs r2, r2, ip, lsl #23 bgt LSYM(Lad_e)#endif @ Exponent too small, denormalize result. mvn r2, r2, asr #23 add r2, r2, #2 orr r0, r3, r0, lsr r2 RET @ Fixup and adjust bit position for denormalized arguments. @ Note that r2 must not remain equal to 0.LSYM(Lad_d): teq r2, #0 eoreq r0, r0, #0x00800000 addeq r2, r2, #(1 << 23) eor r1, r1, #0x00800000 subne r3, r3, #(1 << 23) b LSYM(Lad_x) @ Result is x - x = 0, unless x is INF or NAN.LSYM(Lad_z): mov ip, #0xff000000 and r2, r0, ip, lsr #1 teq r2, ip, lsr #1 moveq r0, ip, asr #2 movne r0, #0 RET @ Overflow: return INF.LSYM(Lad_o): orr r0, r3, #0x7f000000 orr r0, r0, #0x00800000 RET @ At least one of r0/r1 is INF/NAN. @ if r0 != INF/NAN: return r1 (which is INF/NAN) @ if r1 != INF/NAN: return r0 (which is INF/NAN) @ if r0 or r1 is NAN: return NAN @ if opposite sign: return NAN @ return r0 (which is INF or -INF)LSYM(Lad_i): teq r2, ip, lsr #1 movne r0, r1 teqeq r3, ip, lsr #1 RETc(ne) movs r2, r0, lsl #9 moveqs r2, r1, lsl #9 teqeq r0, r1 orrne r0, r3, #0x00400000 @ NAN RET FUNC_END addsf3 FUNC_END subsf3ARM_FUNC_START floatunsisf mov r3, #0 b 1fARM_FUNC_START floatsisf ands r3, r0, #0x80000000 rsbmi r0, r0, #01: teq r0, #0 RETc(eq) mov r1, #0 mov r2, #((127 + 23) << 23) tst r0, #0xfc000000 beq LSYM(Lad_p) @ We need to scale the value a little before branching to code above. tst r0, #0xf0000000 movne r1, r0, lsl #28 movne r0, r0, lsr #4 addne r2, r2, #(4 << 23) tst r0, #0x0c000000 beq LSYM(Lad_p) mov r1, r1, lsr #2 orr r1, r1, r0, lsl #30 mov r0, r0, lsr #2 add r2, r2, #(2 << 23) b LSYM(Lad_p) FUNC_END floatsisf FUNC_END floatunsisf#endif /* L_addsubsf3 */#ifdef L_muldivsf3ARM_FUNC_START mulsf3 @ Mask out exponents. mov ip, #0xff000000 and r2, r0, ip, lsr #1 and r3, r1, ip, lsr #1 @ Trap any INF/NAN. teq r2, ip, lsr #1 teqne r3, ip, lsr #1 beq LSYM(Lml_s) @ Trap any multiplication by 0. bics ip, r0, #0x80000000 bicnes ip, r1, #0x80000000 beq LSYM(Lml_z) @ Shift exponents right one bit to make room for overflow bit. @ If either of them is 0, scale denormalized arguments off line. @ Then add both exponents together. movs r2, r2, lsr #1 teqne r3, #0 beq LSYM(Lml_d)LSYM(Lml_x): add r2, r2, r3, asr #1 @ Preserve final sign in r2 along with exponent for now. teq r0, r1 orrmi r2, r2, #0x8000 @ Convert mantissa to unsigned integer. bic r0, r0, #0xff000000 bic r1, r1, #0xff000000 orr r0, r0, #0x00800000 orr r1, r1, #0x00800000#if __ARM_ARCH__ < 4 @ Well, no way to make it shorter without the umull instruction. @ We must perform that 24 x 24 -> 48 bit multiplication by hand. stmfd sp!, {r4, r5} mov r4, r0, lsr #16 mov r5, r1, lsr #16 bic r0, r0, #0x00ff0000 bic r1, r1, #0x00ff0000 mul ip, r4, r5 mul r3, r0, r1 mul r0, r5, r0 mla r0, r4, r1, r0 adds r3, r3, r0, lsl #16 adc ip, ip, r0, lsr #16 ldmfd sp!, {r4, r5}#else umull r3, ip, r0, r1 @ The actual multiplication.#endif @ Put final sign in r0. mov r0, r2, lsl #16 bic r2, r2, #0x8000 @ Adjust result if one extra MSB appeared. @ The LSB may be lost but this never changes the result in this case. tst ip, #(1 << 15) addne r2, r2, #(1 << 22) movnes ip, ip, lsr #1 movne r3, r3, rrx @ Apply exponent bias, check range for underflow. subs r2, r2, #(127 << 22) ble LSYM(Lml_u) @ Scale back to 24 bits with rounding. @ r0 contains sign bit already. orrs r0, r0, r3, lsr #23 adc r0, r0, ip, lsl #9 @ If halfway between two numbers, rounding should be towards LSB = 0. mov r3, r3, lsl #9 teq r3, #0x80000000 biceq r0, r0, #1 @ Note: rounding may have produced an extra MSB here. @ The extra bit is cleared before merging the exponent below. tst r0, #0x01000000 addne r2, r2, #(1 << 22) @ Check for exponent overflow cmp r2, #(255 << 22) bge LSYM(Lml_o) @ Add final exponent. bic r0, r0, #0x01800000 orr r0, r0, r2, lsl #1 RET @ Result is 0, but determine sign anyway.LSYM(Lml_z): eor r0, r0, r1 bic r0, r0, #0x7fffffff RET @ Check if denormalized result is possible, otherwise return signed 0.LSYM(Lml_u): cmn r2, #(24 << 22) RETc(le) @ Find out proper shift value.
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