?? soundex2a.py
字號:
"""Soundex algorithmThis program is part of "Dive Into Python", a free Python book forexperienced programmers. Visit http://diveintopython.org/ for thelatest version."""__author__ = "Mark Pilgrim (mark@diveintopython.org)"__version__ = "$Revision: 1.3 $"__date__ = "$Date: 2004/05/11 19:11:21 $"__copyright__ = "Copyright (c) 2004 Mark Pilgrim"__license__ = "Python"import string, recharToSoundex = {"A": "9", "B": "1", "C": "2", "D": "3", "E": "9", "F": "1", "G": "2", "H": "9", "I": "9", "J": "2", "K": "2", "L": "4", "M": "5", "N": "5", "O": "9", "P": "1", "Q": "2", "R": "6", "S": "2", "T": "3", "U": "9", "V": "1", "W": "9", "X": "2", "Y": "9", "Z": "2"}def soundex(source): "convert string to Soundex equivalent" # Soundex requirements: # source string must be at least 1 character # and must consist entirely of letters if (not source) or (not source.isalpha()): return "0000" # Soundex algorithm: # 1. make first character uppercase # 2. translate all other characters to Soundex digits source = source.upper() digits = source[0] + "".join(map(lambda c: charToSoundex[c], source[1:])) # 3. remove consecutive duplicates digits2 = digits[0] for d in digits[1:]: if digits2[-1] != d: digits2 += d # 4. remove all "9"s digits3 = re.sub('9', '', digits2) # 5. pad end with "0"s to 4 characters while len(digits3) < 4: digits3 += "0" # 6. return first 4 characters return digits3[:4]if __name__ == '__main__': from timeit import Timer names = ('Woo', 'Pilgrim', 'Flingjingwaller') for name in names: statement = "soundex('%s')" % name t = Timer(statement, "from __main__ import soundex") print name.ljust(15), soundex(name), min(t.repeat())
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