/* `long long int' divison with remainder.   Copyright (C) 1992, 1996, 1997 Free Software Foundation, Inc.   This file is part of the GNU C Library.   The GNU C Library is free software; you can redistribute it and/or   modify it under the terms of the GNU Lesser General Public   License as published by the Free Software Foundation; either   version 2.1 of the License, or (at your option) any later version.   The GNU C Library is distributed in the hope that it will be useful,   but WITHOUT ANY WARRANTY; without even the implied warranty of   MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU   Lesser General Public License for more details.   You should have received a copy of the GNU Lesser General Public   License along with the GNU C Library; if not, write to the Free   Software Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA   02111-1307 USA.  */#define _GNU_SOURCE#include <features.h>#include <stdlib.h>/* Return the `lldiv_t' representation of NUMER over DENOM.  */lldiv_tlldiv (long long int numer, long long int denom){    lldiv_t result;    result.quot = numer / denom;    result.rem = numer % denom;    /* The ANSI standard says that |QUOT| <= |NUMER / DENOM|, where       NUMER / DENOM is to be computed in infinite precision.  In       other words, we should always truncate the quotient towards       zero, never -infinity.  Machine division and remainer may       work either way when one or both of NUMER or DENOM is       negative.  If only one is negative and QUOT has been       truncated towards -infinity, REM will have the same sign as       DENOM and the opposite sign of NUMER; if both are negative       and QUOT has been truncated towards -infinity, REM will be       positive (will have the opposite sign of NUMER).  These are       considered `wrong'.  If both are NUM and DENOM are positive,       RESULT will always be positive.  This all boils down to: if       NUMER >= 0, but REM < 0, we got the wrong answer.  In that       case, to get the right answer, add 1 to QUOT and subtract       DENOM from REM.  */    if (numer >= 0 && result.rem < 0)    {	++result.quot;	result.rem -= denom;    }    return result;}#if __WORDSIZE != 64#undef imaxdivweak_alias (lldiv, imaxdiv);#endif