?? cm_sm33.m
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% 注意這里和cm_sm32程序的區別是信號在信道上只考慮了加性白噪聲
% 沒有瑞利衰落; 其他的都是一樣的;
function [pb1,ps1]=cm_sm32(snr_in_dB)
% [pb,ps]=cm_sm32(snr_in_dB)
% CM_SM3 finds the probability of bit error
% and symbol error for
% the given value of snr_in_dB, signal to noise ratio in dB.
N=100;
E=1; % energy per symbol
snr=10^(snr_in_dB/10); % signal to noise ratio
sgma=sqrt(E/snr)/2; % noise variance
% signal mapping
s00=[1 0]; s01=[0 1]; s11=[-1 0]; s10=[0 -1];
% generation of the data source
numofsymbolerror=0;
numofbiterror=0;
counter=0;
while(numofbiterror<100)
for i=1:N
% a uniform random variable between 0 and 1
temp=rand;
% with probability 1/4, source output is "00"
if (temp<0.25)
dsource1(i)=0; dsource2(i)=0;
% with probability 1/4, source output is "01"
elseif (temp<0.5)
dsource1(i)=0; dsource2(i)=1;
% with probability 1/4, source output is "10"
elseif (temp<0.75)
dsource1(i)=1; dsource2(i)=0;
% with probability 1/4, source output is "11"
else
dsource1(i)=1; dsource2(i)=1;
end;
end;
% detection and the probability of error calculation
for i=1:N
% the received signal at the detection,
% for the ith symbol,is:
% 2 normal distributed r.v with 0, variance sgma
% 注意這里和cm_sm32程序的區別是信號在信道上只考慮了加性白噪聲
% 沒有瑞利衰落;
n=sgma*randn(1,2);
if ((dsource1(i)==0) & (dsource2(i)==0))
r=s00+n;
elseif ((dsource1(i)==0) & (dsource2(i)==1))
r=s01+n;
elseif ((dsource1(i)==1) & (dsource2(i)==0))
r=s10+n;
else
r=s11+n;
end;
% The correlation metrics are computed below
c00=dot(r,s00); c01=dot(r,s01);
c10=dot(r,s10); c11=dot(r,s11);
% The decision on the ith symbol is made next
c_max=max([c00,c01,c10,c11]);
if (c00==c_max)
decis1=0; decis2=0;
elseif (c01==c_max)
decis1=0; decis2=1;
elseif (c10==c_max)
decis1=1; decis2=0;
else
decis1=1; decis2=1;
end;
% Increment the error counter,
% if the decision is not correct
symbolerror=0;
if (decis1~=dsource1(i))
numofbiterror=numofbiterror+1; symbolerror=1;
end;
if (decis2~=dsource2(i))
numofbiterror=numofbiterror+1; symbolerror=1;
end;
if (symbolerror==1)
numofsymbolerror=numofsymbolerror+1;
end;
end;
counter=counter+1;
end;
% since there are totally N symbols
ps1=numofsymbolerror/(N*counter);
% since 2N bits are transmitted
pb1=numofbiterror/(2*N*counter);
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