/* Allocate memory region filled with spaces.   Copyright (C) 1991 Free Software Foundation, Inc.This file is part of the libiberty library.Libiberty is free software; you can redistribute it and/ormodify it under the terms of the GNU Library General PublicLicense as published by the Free Software Foundation; eitherversion 2 of the License, or (at your option) any later version.Libiberty is distributed in the hope that it will be useful,but WITHOUT ANY WARRANTY; without even the implied warranty ofMERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNULibrary General Public License for more details.You should have received a copy of the GNU Library General PublicLicense along with libiberty; see the file COPYING.LIB.  Ifnot, write to the Free Software Foundation, Inc., 59 Temple Place - Suite 330,Boston, MA 02111-1307, USA.  *//*NAME	spaces -- return a pointer to a buffer full of spacesSYNOPSIS	char *spaces (int count)DESCRIPTION	Returns a pointer to a memory region filled with the specified	number of spaces and null terminated.  The returned pointer is	valid until at least the next call.	BUGS*/#include "ansidecl.h"#include "libiberty.h"#if VMS#include <stdlib.h>#include <unixlib.h>#else/* For systems with larger pointers than ints, these must be declared.  */extern PTR malloc PARAMS ((size_t));extern void free PARAMS ((PTR));#endifconst char *spaces (count)  int count;{  register char *t;  static char *buf;  static int maxsize;  if (count > maxsize)    {      if (buf)	{	  free (buf);	}      buf = malloc (count + 1);      if (buf == (char *) 0)	return 0;      for (t = buf + count ; t != buf ; )	{	  *--t = ' ';	}      maxsize = count;      buf[count] = '\0';    }  return (const char *) (buf + maxsize - count);}