?? updown1.m
字號(hào):
% updown1.m
% up-down algorithm
N = 25; % number to test
count = 0; % iteration count
while N>1
if rem(N,2)==0 % even
N = N/2;
count = count+1;
else % odd
N = (3*N+1)/2;
count = count+2;
end
end
count
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