%獲得網(wǎng)絡(luò)的輸入樣本P和目標(biāo)樣本T
P=[1 0.6 0.1 0 0 0 0   1 0.5 0 0 0 0 0;
1 0.6 0.1 0 0 0 0   0 0.5 1 0.4 0 0 0;
1 0.6 0.1 0 0 0 0   0 0 0 0.4 1 0.6 0;
1 0.6 0.1 0 0 0 0   0 0 0 0 0 0 0.8;
0 0.6 0.6 0 0 0 0   1 0.5 0 0 0 0 0;
0 0.6 0.6 0 0 0 0   0 0.5 1 0.4 0 0 0;
0 0.6 0.6 0 0 0 0   0 0 0 0.4 1 0.6 0;
0 0.6 0.6 0 0 0 0   0 0 0 0 0 0 0.8;
0 0 0.6 1 0 0 0    1 0.5 0 0 0 0 0;
0 0 0.6 1 0 0 0    0 0.5 1 0.4 0 0 0;
0 0 0.6 1 0 0 0    0 0 0 0.4 1 0.6 0;
0 0 0.6 1 0 0 0    0 0 0 0 0 0 0.8;
0 0 0 0 1 0.6 0    1 0.5 0 0 0 0 0;
0 0 0 0 1 0.6 0    0 0.5 1 0.4 0 0 0;
0 0 0 0 1 0.6 0    0 0 0 0.4 1 0.6 0;
0 0 0 0 1 0.6 0    0 0 0 0 0 0 0.8]';
T=[1 0.5 0 0 0 0 0 0;
0 0 0 0.2 0.6 1 0.6 0.2;
0 0 0 0.2 0.6 1 0.6 0.2;
0 0 0 0.2 0.6 1 0.6 0.2;
0.4 0.8 1 0.8 0.4 0.2 0 0;
0 0 0 0.2 0.6 1 0.6 0.2;
0 0 0 0 0 0.2 0.5 0.8;
0 0 0 0.2 0.6 1 0.6 0.2;
0 0 0 0.2 0.6 1 0.6 0.2;
0 0 0 0.2 0.6 1 0.6 0.2;
0 0 0 0 0 0.2 0.5 0.8;
0 0 0 0 0 0.2 0.5 0.8;
0 0 0 0.2 0.6 1 0.6 0.2;
0 0 0 0.2 0.6 1 0.6 0.2;
0 0 0 0 0 0.2 0.5 0.8;
0 0 0 0 0 0.2 0.5 0.8]';
%根據(jù)Kolmogorov定理，輸入層有14個節(jié)點，所以中間層有29個節(jié)點
%中間層神經(jīng)元的傳遞函數(shù)為'tansig'
%輸出層有8個節(jié)點，其神經(jīng)元傳遞函數(shù)為logsig
%訓(xùn)練函數(shù)采用traingdx
net=newff(minmax(P),[29,8],{'tansig','logsig'},'traingdx');
%訓(xùn)練步數(shù)為1000次
%訓(xùn)練目標(biāo)誤差為0.001
net.trainParam.epochs=1000;
net.trainParam.goal=0.001;
net=train(net,P,T);
Y=sim(net,P);
%求訓(xùn)練值在每一個點上的誤差
for i=1:16
    x(i)=norm(Y(:,i));
end
plot(1:16,x);