?? usaco 2_4_2 overfencing 題解_leokan的blog.mht
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}
for(i=3D1; i<ht; i+=3D2) {
lookexit(Pt(i, 0), Pt(i, 1));
lookexit(Pt(i, wid-1), Pt(i, wid-2));
}
/* must have found at least one square with an exit */
/* since two exits might open onto the same square, perhaps eq =
=3D=3D 1 */
assert(eq =3D=3D 1 || eq =3D=3D 2);=20
for(bq =3D 0; bq < eq; bq++) {
p =3D floodq[bq].p;
d =3D floodq[bq].d;
dist[p.r][p.c] =3D d;
addqueue(d, p, Pt(p.r-2, p.c));
addqueue(d, p, Pt(p.r+2, p.c));
addqueue(d, p, Pt(p.r, p.c-2));
addqueue(d, p, Pt(p.r, p.c+2));
}
/* find maximum distance */
m =3D 0;
for(r=3D0; r<ht; r++)
for(c=3D0; c<wid; c++)
if(dist[r][c] > m)
m =3D dist[r][c];
fprintf(fout, "%d\n", m);
exit(0);
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D(html, '</table></div><div class=3D"line"> </div>');
var div =3D document.getElementById('in_related_tmp');
if(div){
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while(div.firstChild){
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}
div.parentNode.removeChild(div);
}
}
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script.type =3D 'text/javascript';
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