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<html><table height="500" width="1000" border="2"><TR height="5" width="1000"><strong><center><marquee><font color="Green"><h1>APTITUDE</h1></center></strong></font></TR></marquee><TR><TD align="left" width="200" valign="top"><table><TR><a href="numbers.html"><strong>Numbers</strong></a></TR><br><TR><a href="hcf.html"><strong>H.C.F and L.C.M</strong></a></TR><br><TR><a href="dec.html" target="right"><strong>Decimal Fractions</strong></a></TR><br><TR><a href="simplification.html"><strong>Simplification</strong></a></TR><br><TR><a href="squareandcuberoot.html" target="right"><strong>Square and Cube roots</strong></a></TR><br><TR><a href="average.html" ><strong>Average</strong></a></TR><br><TR><a href="pnumbers.html" ><strong>Problems on Numbers</strong></a></TR><br><TR><a href="problemsonages.html"><strong>Problems on Ages</strong></a></TR><br><TR><a href="surdsandindices.html"><strong>Surds and Indices</strong></a></TR><br><TR><a href="percent.html" target="right"><strong>Percentage</strong></a></TR><br><TR><a href="profitandloss.html" target="right"><strong>Profit and Loss</strong></a></TR><br><TR><a href="ratioandproportion.html" target="right"><strong>Ratio And Proportions</strong></a></TR><br><TR><a href="partnership.html"><strong>Partnership</strong></a></TR><br><TR><a href="chainrule1.html"><strong>Chain Rule</strong></a></TR><br><TR><a href="timeandwork.html" target="right"><strong>Time and Work</strong></a></TR><br><TR><a href="pipesandcisterns.html" target="right"><strong>Pipes and Cisterns</strong></a></TR><br><TR><a href="timeanddistance.html"><strong>Time and Distance</strong></a></TR><br><TR><a href="trains.html" target="right"><strong>Trains</strong></a></TR><br><TR><a href="boats.html"><strong>Boats and Streams</strong></a></TR><br><TR><a href="alligation.html"><strong>Alligation or Mixture </strong></a></TR><br><TR><a href="simple.html" target="right"><strong>Simple Interest</strong></a></TR><br><TR><a href="CI.html" target="right"><strong>Compound Interest</strong></a></TR><br><TR><a href=""><strong>Logorithms</strong></a></TR><br><TR><a href="areas.html" target="right"><strong>Areas</strong></a></TR><br><TR><a href="volume.html" target="right"><strong>Volume and Surface area</strong></a></TR><br><TR><a href="races.html" target="right"><strong>Races and Games of Skill</strong></a></TR><br><TR><a href="calendar.html" target="right"><strong>Calendar</strong></a></TR><br><TR><a href="clocks.html" target="right"><strong>Clocks</strong></a></TR><br><TR><a href="" target="right"><strong>Stocks ans Shares</strong></a></TR><br><TR><a href="true.html" target="right"><strong>True Discount</strong></a></TR><br><TR><a href="banker1.html" target="right"><strong>Bankers Discount</strong></a></TR><br><TR><a href="oddseries.html" target="right"><strong>Oddmanout and Series</strong></a></TR><br><TR><a href=""><strong>Data Interpretation</strong></a></TR><br><TR><a href="probability.html"><strong>probability</strong></a></TR><br><TR><a href="percom1.html" target="right" ><strong>Permutations and Combinations</strong></a></TR><br><TR><a href="pinkivijji_puzzles.html" target="right"><strong>Puzzles</strong></a></TR></table></TD><TD valign="top"><a href="simple.html" target="right"><strong>BACK</strong></a><br><br><font size="5"><center><b><u>MEDIUM PROBLEMS</u></b></center></font><font size="4"><pre>1. A sum at Simple interest at 13 1/2% per annum amounts to Rs 2502.50 after 4 years.Find the sum. Sol:- Let Sum be x. then, S.I = (P*T*R)/100 = ((x*4*27)/(100*2)) = 27x/100 Amount = (x+(27x)/100) = 77x/50 77x/50 = 2502.50 x = (2502.50*50)/77 = 1625 Sum = 1625 2. A some of money becomes double of itself in 4 years in 12 years it will become how many times at the same rate. Sol:- 4 yrs - - - - - - - - - P 12 yrs - - - - - - - - - ? (12/4)* P =3P Amount or Sum = P+3P = 4 times 3. A Sum was put at S.I at a certain rate for 3 years.Had it been put at 2% higher rate ,it would have fetched Rs 360 more .Find the Sum. Sol:- Let Sum =P original rate = R T = 3 years If 2% is more than the original rate ,it would have fetched 360 more ie., R+2 (P*(R+2)*3/100) - (P*R*3)/100 = 360 3PR+ 6P-3PR = 36000 6P = 36000 P = 6000 Sum = 6000. 4.Rs 800 amounts to Rs 920 in 3yrs at S.I.If the interest rate is increased by 3%, it would amount to how much? Sol:- S.I = 920 - 800 = 120 Rate = (100*120)/(800*3) = 5% New Rate = 5 + 3 = 8% , Principal = 800 , Time = 3 yrs S.I = (800*8*3)/100 = 192 New Amount = 800 + 192 = 992 5. Prabhat took a certain amount as a loan from bank at the rate of 8% p.a S.I and gave the same amount to Ashish as a loan at the rate of 12% p.a . If at the end of 12 yrs, he made a profit of Rs. 320 in the deal,What was the original amount? Sol:- Let the original amount be Rs x. T = 12 R1 = 8% R2 = 12% Profit = 320 P = x (P*T*R2)/100 - (P*T*R1)/100 =320 (x*12*12)/100 - (x*8*12)/100 = 320 x = 2000/3 x = Rs.666.67 6. Simple Interest on a certail sum at a certain rate is 9/16 of the sum . if the number representing rate percent and time in years be equal ,then the rate is. Sol:- Let Sum = x .Then, S.I = 9x/16 Let time = n years & rate = n% n = 100 * 9x/16 * 1/x * 1/n n * n = 900/16 n = 30/4 = 7 1/2% <font size="3"><a href="simple.html" target="right"><strong>BACK</strong></a></font></pre></font></TD></TR></table></html>?? 快捷鍵說明
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