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<html><table height="500" width="1000" border="2"><TR height="5" width="1000"><strong><center><marquee><font color="Green"><h1>APTITUDE</h1></center></strong></font></TR></marquee><TR><TD align="left" width="200" valign="top"><table><TR><a href="numbers.html"><strong>Numbers</strong></a></TR><br><TR><a href="hcf.html"><strong>H.C.F and L.C.M</strong></a></TR><br><TR><a href="dec.html" target="right"><strong>Decimal Fractions</strong></a></TR><br><TR><a href="simplification.html"><strong>Simplification</strong></a></TR><br><TR><a href="squareandcuberoot.html" target="right"><strong>Square and Cube roots</strong></a></TR><br><TR><a href="average.html" ><strong>Average</strong></a></TR><br><TR><a href="pnumbers.html" ><strong>Problems on Numbers</strong></a></TR><br><TR><a href="problemsonages.html"><strong>Problems on Ages</strong></a></TR><br><TR><a href="surdsandindices.html"><strong>Surds and Indices</strong></a></TR><br><TR><a href="percent.html" target="right"><strong>Percentage</strong></a></TR><br><TR><a href="profitandloss.html" target="right"><strong>Profit and Loss</strong></a></TR><br><TR><a href="ratioandproportion.html" target="right"><strong>Ratio And Proportions</strong></a></TR><br><TR><a href="partnership.html"><strong>Partnership</strong></a></TR><br><TR><a href="chainrule1.html"><strong>Chain Rule</strong></a></TR><br><TR><a href="timeandwork.html" target="right"><strong>Time and Work</strong></a></TR><br><TR><a href="pipesandcisterns.html" target="right"><strong>Pipes and Cisterns</strong></a></TR><br><TR><a href="timeanddistance.html"><strong>Time and Distance</strong></a></TR><br><TR><a href="trains.html" target="right"><strong>Trains</strong></a></TR><br><TR><a href="boats.html"><strong>Boats and Streams</strong></a></TR><br><TR><a href="alligation.html"><strong>Alligation or Mixture </strong></a></TR><br><TR><a href="simple.html" target="right"><strong>Simple Interest</strong></a></TR><br><TR><a href="CI.html" target="right"><strong>Compound Interest</strong></a></TR><br><TR><a href=""><strong>Logorithms</strong></a></TR><br><TR><a href="areas.html" target="right"><strong>Areas</strong></a></TR><br><TR><a href="volume.html" target="right"><strong>Volume and Surface area</strong></a></TR><br><TR><a href="races.html" target="right"><strong>Races and Games of Skill</strong></a></TR><br><TR><a href="calendar.html" target="right"><strong>Calendar</strong></a></TR><br><TR><a href="clocks.html" target="right"><strong>Clocks</strong></a></TR><br><TR><a href="" target="right"><strong>Stocks ans Shares</strong></a></TR><br><TR><a href="true.html" target="right"><strong>True Discount</strong></a></TR><br><TR><a href="banker1.html" target="right"><strong>Bankers Discount</strong></a></TR><br><TR><a href="oddseries.html" target="right"><strong>Oddmanout and Series</strong></a></TR><br><TR><a href=""><strong>Data Interpretation</strong></a></TR><br><TR><a href="probability.html"><strong>probability</strong></a></TR><br><TR><a href="percom1.html" target="right" ><strong>Permutations and Combinations</strong></a></TR><br><TR><a href="pinkivijji_puzzles.html" target="right"><strong>Puzzles</strong></a></TR></table></TD><TD valign="top"><font size="4" color="Purple"><center><B><U>CALENDAR</U></B></center></font><a href="calendar.html" target="right"><strong>BACK</strong></a><br><br><FONT size="4"><bold><u><h3>Typical problems</h3></u><pre> Problem 1 : on what dates of october,1994 did monday fall ? Solution : 01 01 94 23 ------- total = 119 Then (119)/7 = (17) = 0 odd days so the day is saturday Therefore in october first the day is saturday.so, the monday fell <br>on 3rd october 1994.During october 1994, monday fell on <br>3rd ,10th,17th and 24th. Problem 2 : How many days are there from 2nd january 1995 o 15 th march,1995 ? Solution : Jan + Feb + March 30 + 28 + 15 = 73 days Problem 3 : The year next to 1996 having the same calendar as that of 1996 is ? Solution : Starting with 1996 , we go on countig the number of odd days<br> till the sum is divisible by 7. Year 1996 1997 1998 1999 2000 odd days 2 1 1 1 2 2 + 1 + 1 + 1 + 2 = 7 odd days i.e odd day. Therefore calendar for 2001 will be the same as that of 1995. Problem 4 : The calendar for 1990 is same as for : Solution : count the number of days 1990 onwards to get 0 odd day. Year 1990 1991 1992 1993 1994 1995 odd days 1 1 2 1 1 1 1 + 1 + 2 + 1 + 1 + 1 = 7 or 0 odd days Therefore calendar for 1990 is the same as for the year 1996. Problem 5 : The day on 5th march of year is the same day on what date of <br>the same year? Solution : In the given monthly code table represents the march code and <br>november code both are same.that means any date in march is the same <br>day of week as the corresponding date in november of that year, so the same day<br> falls on 5th november.<br><br> </bold></pre></bold></center></FONT><a href="calendar.html" target="right"><strong>BACK</strong></a><br><br></TD></TR></table></html>?? 快捷鍵說明
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