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<html><table height="500" width="1000" border="2"><TR height="5" width="1000"><strong><center><marquee><font color="Green"><h1>APTITUDE</h1></center></strong></font></TR></marquee><TR><TD align="left" width="200" valign="top"><table><TR><a href="numbers.html"><strong>Numbers</strong></a></TR><br><TR><a href="hcf.html"><strong>H.C.F and L.C.M</strong></a></TR><br><TR><a href="dec.html" ><strong>Decimal Fractions</strong></a></TR><br><TR><a href="simplification.html"><strong>Simplification</strong></a></TR><br><TR><a href="squareandcuberoot.html" ><strong>Square and Cube roots</strong></a></TR><br><TR><a href="average.html" ><strong>Average</strong></a></TR><br><TR><a href="pnumbers.html" ><strong>Problems on Numbers</strong></a></TR><br><TR><a href="problemsonages.html"><strong>Problems on Ages</strong></a></TR><br><TR><a href="surdsandindices.html"><strong>Surds and Indices</strong></a></TR><br><TR><a href="percent.html" ><strong>Percentage</strong></a></TR><br><TR><a href="profitandloss.html" ><strong>Profit and Loss</strong></a></TR><br><TR><a href="ratioandproportion.html" ><strong>Ratio And Proportions</strong></a></TR><br><TR><a href="partnership.html"><strong>Partnership</strong></a></TR><br><TR><a href="chainrule1.html"><strong>Chain Rule</strong></a></TR><br><TR><a href="timeandwork.html" ><strong>Time and Work</strong></a></TR><br><TR><a href="pipesandcisterns.html" ><strong>Pipes and Cisterns</strong></a></TR><br><TR><a href="timeanddistance.html"><strong>Time and Distance</strong></a></TR><br><TR><a href="trains.html" ><strong>Trains</strong></a></TR><br><TR><a href="boats.html"><strong>Boats and Streams</strong></a></TR><br><TR><a href="alligation.html"><strong>Alligation or Mixture </strong></a></TR><br><TR><a href="simple.html" ><strong>Simple Interest</strong></a></TR><br><TR><a href="CI.html"><strong>Compound Interest</strong></a></TR><br><TR><a href=""><strong>Logorithms</strong></a></TR><br><TR><a href="areas.html" ><strong>Areas</strong></a></TR><br><TR><a href="volume.html"><strong>Volume and Surface area</strong></a></TR><br><TR><a href="races.html" ><strong>Races and Games of Skill</strong></a></TR><br><TR><a href="calendar.html" ><strong>Calendar</strong></a></TR><br><TR><a href="clocks.html" ><strong>Clocks</strong></a></TR><br><TR><a href="" ><strong>Stocks ans Shares</strong></a></TR><br><TR><a href="true.html" ><strong>True Discount</strong></a></TR><br><TR><a href="banker1.html" ><strong>Bankers Discount</strong></a></TR><br><TR><a href="oddseries.html"><strong>Oddmanout and Series</strong></a></TR><br><TR><a href=""><strong>Data Interpretation</strong></a></TR><br><TR><a href="probability.html"><strong>probability</strong></a></TR><br><TR><a href="percom1.html" ><strong>Permutations and Combinations</strong></a></TR><br><TR><a href="pinkivijji_puzzles.html" ><strong>Puzzles</strong></a></TR></table></TD><TD valign="top" ><a href="clocks.html"><b>BACK</b></a><h2 align="center"><b>CLOCKS</b></h2><br><br><b>Simple Problems</b><u><b>Shortcuts in clocks </b></u> :<br><br><u><b>Type1</b></u>: Find the angle between the hour hand and the minute hand <br>of a clock when the time is 3.25<br>solution : In this type of problems the formulae is as follows<br> 30*[hrs-(min/5)]+(min/2)<br> In the above problem the given data is time is 3.25. that is applied in the<br> formulae <br> 30*[3-(25/5)]+(25/2)30*(15-25)/5+25/2<br> = 30*(-10/5)+25/2<br> = -300/5+25/2<br> = -600+(25/2)=-475/10=-47.5<br> i.e 47 1/20<br> therefore the required angle is 47 1/20.<br> Note :the -sign must be neglected.<br> <u>Another shortcut for type1 is</u> :<br> The formulae is <br> 6*x-(hrs*60+X)/2<br> Here x is the given minutes,<br> so in the given problem the minutes is 25 minutes,<br> that is applied in the given formulae<br> 6*25-(3*60+25)/2<br> 150-205/2<br> (300-205)/2=95/2<br> =47 1/20.<br> therefore the required angle is 47 1/20.<br><br><br><b><u>Type2</u></b> : At what time between 2 and 3 o' clock will be<br> the hands of a clock be together?<br>Solution : In this type of problems the formulae is <br> 5*x*(12/11)<br> Here x is replaced by the first interval of given time. here i.e 2.<br> In the above problem the given data is between 2 and 3 o' clock<br> 5*2*12/11 =10*12/11=120/11=10 10/11min.<br> Therefore the hands will coincide at 10 10/11 min.past2.<br><br> <u>Another shortcut for type2 is</u> : Here the clocks be together but not opposite <br>to each other so the angle is 0 degrees. so the formulae is <br> 6*x-(2*60+x)/2=06*x-(120+x)/2=012x-120-x=0<br> 11x=120<br> x=120/11=10 10/11<br> therefore the hands will be coincide at 10 10/11 min.past2.<br></bold></TD></TR></table></body></html>?? 快捷鍵說明
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