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<html><table height="500" width="1000" border="2"><TR height="5" width="1000"><strong><center><marquee><font color="Green"><h1>APTITUDE</h1></center></strong></font></TR></marquee><TR><TD align="left" width="200" valign="top"><table><TR><a href="numbers.html"><strong>Numbers</strong></a></TR><br><TR><a href="hcf.html"><strong>H.C.F and L.C.M</strong></a></TR><br><TR><a href="dec.html" ><strong>Decimal Fractions</strong></a></TR><br><TR><a href="simplification.html"><strong>Simplification</strong></a></TR><br><TR><a href="squareandcuberoot.html" ><strong>Square and Cube roots</strong></a></TR><br><TR><a href="average.html" ><strong>Average</strong></a></TR><br><TR><a href="pnumbers.html" ><strong>Problems on Numbers</strong></a></TR><br><TR><a href="problemsonages.html"><strong>Problems on Ages</strong></a></TR><br><TR><a href="surdsandindices.html"><strong>Surds and Indices</strong></a></TR><br><TR><a href="percent.html" ><strong>Percentage</strong></a></TR><br><TR><a 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><strong>Areas</strong></a></TR><br><TR><a href="volume.html"><strong>Volume and Surface area</strong></a></TR><br><TR><a href="races.html" ><strong>Races and Games of Skill</strong></a></TR><br><TR><a href="calendar.html" ><strong>Calendar</strong></a></TR><br><TR><a href="clocks.html" ><strong>Clocks</strong></a></TR><br><TR><a href="" ><strong>Stocks ans Shares</strong></a></TR><br><TR><a href="true.html" ><strong>True Discount</strong></a></TR><br><TR><a href="banker1.html" ><strong>Bankers Discount</strong></a></TR><br><TR><a href="oddseries.html"><strong>Oddmanout and Series</strong></a></TR><br><TR><a href=""><strong>Data Interpretation</strong></a></TR><br><TR><a href="probability.html"><strong>probability</strong></a></TR><br><TR><a href="percom1.html" ><strong>Permutations and Combinations</strong></a></TR><br><TR><a href="pinkivijji_puzzles.html" ><strong>Puzzles</strong></a></TR></table></TD><TD valign="top"><a href="pnumbers.html" name="right"><b>BACK</b></a><font size="5"><center><b>PROBLEMS ON NUMBERS</b></center></font><br><br> <font size="5"><b>SOLVED PROBLEMS</b></font><br><br><br><br> <font size="4"> <b>Medium Problems</b>:<br><br><br>12.The difference between two numbers 1365.When the larger <br>number is divided by the smaller one the quotient is 6 and <br>the remainder is 15.The smaller number is?<br><br>a.240 b.270 c.295 d.360<br>Solution:<br>Let the smaller number be x, then larger number =1365+x<br> <br>Therefore 1365+x=6x+15<br> 5x=1350 => x=270<br> Required number is 270.<br><br>13.Find the remainder when 231 is divided by 5?<br>Solution:<br>210 =1024.<br>unit digit of 210 * 210 * 210 is 4 <br>as 4*4*4 gives unit digit 4<br>unit digit of 231 is 8.<br>Now 8 when divided by 5 gives 3 as remainder.<br> 231 when divided by 5 gives 3 as remainder.<br><br>14.The largest four digit number which when divided by 4,7 or 13 leaves a remainder of 3 in each case is?<br><br>a.8739 b.9831 c.9834 d.9893.Solution:<br> Greatest number of four digits is 9999<br> L.C.M of 4,7, and 13=364.<br> On dividing 9999 by 364 remainder obtained is 171.<br> Therefore greatest number of four digits divisible by 4,7,13<br> =9999-171=9828.<br> Hence required number=9828+3=9831. <br> Ans (b).<br><br>15.What least value must be assigned to * so that th number 197*5462 is divisible by 9?<br><br>Solution: <br> Let the missing digit be x<br> Sum of digits = (1+9+7+x+5+4+6+2)=34+x<br> For 34+x to be divisible by 9 , x must be replaced by 2<br> The digit in place of x must be 2.<br><br>16.Find the smallest number of 6 digits which is exactly divisible by 111?<br>Solution:<br> Smallest number of 6 digits is 100000<br> On dividing 10000 by 111 we get 100 as remainder<br> Number to be added =111-100=11.<br> Hence,required number =10011.<br><br>17.A number when divided by 342 gives a remainder 47.When the same<br> number is divided by 19 what would be the remainder?<br><br>Solution:<br>Number=342 K + 47 = 19 * 18 K + 19 * 2 + 9=19 ( 18K + 2) + 9.<br>The given number when divided by 19 gives 18 K + 2 as quotient <br>and 9 as remainder.<br><br>18.In doing a division of a question with zero remainder,a candidate <br>took 12 as divisor instead of 21.The quotient obtained by him was 35.<br>The correct quotient is?<br><br>a.0 b.12 c.13 d.20<br>Solution:<br>Dividend=12*35=420.<br> Now dividend =420 and divisor =21.<br>Therefore correct quotient =420/21=20.<br><br>19.If a number is multiplied by 22 and the same number is<br> added to it then we get a number that is half the square <br>of that number. Find the number.<br><br>a.45 b.46 c.47 d. none<br>Solution:<br>Let the required number be x.<br>Given that x*22+x = 1/2 x2<br> 23x = 1/2 x2<br> x = 2*23=46 <br> <br>Ans (b)<br><br>20.Find the number of zeros in the factorial of the number 18?<br><br>Solution:<br>18! contains 15 and 5,which combined with one even number<br> gives zeros. Also 10 is also contained in 18! which will<br> give additional zero .Hence 18! contains 3 zeros and the <br>last digit will always be zero.<br><br>21.The sum of three prime numbers is 100.If one of them <br>exceeds another by 36 then one of the numbers is?<br><br>a.7 b.29 c.41 d67.<br><br>Solution:<br><br>x+(x+36)+y=100<br> 2x+y=64<br> Therefore y must be even prime which is 2<br> 2x+2=64=>x=31.<br>Third prime number =x+36=31+36=67.<br><br>22.A number when divided by the sum of 555 and 445 gives <br>two times their difference as quotient and 30 as remainder .<br>The number is?<br><br>a.1220 b.1250 c.22030 d.220030.<br><br>Solution:<br>Number=(555+445)*(555-445)*2+30<br> =(555+445)*2*110+30<br> =220000+30=220030.<br><br>23.The difference of 1025-7 and 1024+x is divisible by 3 for x=?<br><br>a.3 b.2 c.4 d.6<br><br>Solution: <br>The difference of 1025-7 and 1024+x is<br> =(1025-7)-(1024-x)<br> =1025-7-1024-x<br> =10.1024-7 -1024-x<br> =1024(10-1)-(7-x)<br> =1024*9-(7+x)<br><br>The above expression is divisible by 3 so we have to<br> replace x with 2.<br><br>Ans (b).<br><br><a href="pnumbers.html" ><b>BACK</b></a> <br><br></font></TD></TR></table></html>?? 快捷鍵說明
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