# 2001 September 15## The author disclaims copyright to this source code.  In place of# a legal notice, here is a blessing:##    May you do good and not evil.#    May you find forgiveness for yourself and forgive others.#    May you share freely, never taking more than you give.##***********************************************************************# This file implements regression tests for SQLite library.  The# focus of this file is testing aggregate functions and the# GROUP BY and HAVING clauses of SELECT statements.## $Id: select3.test,v 1.18 2005/11/14 22:29:06 drh Exp $set testdir [file dirname $argv0]source $testdir/tester.tcl# Build some test data#do_test select3-1.0 {  execsql {    CREATE TABLE t1(n int, log int);    BEGIN;  }  for {set i 1} {$i<32} {incr i} {    for {set j 0} {pow(2,$j)<$i} {incr j} {}    execsql "INSERT INTO t1 VALUES($i,$j)"  }  execsql {    COMMIT  }  execsql {SELECT DISTINCT log FROM t1 ORDER BY log}} {0 1 2 3 4 5}# Basic aggregate functions.#do_test select3-1.1 {  execsql {SELECT count(*) FROM t1}} {31}do_test select3-1.2 {  execsql {    SELECT min(n),min(log),max(n),max(log),sum(n),sum(log),avg(n),avg(log)    FROM t1  }} {1 0 31 5 496 124 16.0 4.0}do_test select3-1.3 {  execsql {SELECT max(n)/avg(n), max(log)/avg(log) FROM t1}} {1.9375 1.25}# Try some basic GROUP BY clauses#do_test select3-2.1 {  execsql {SELECT log, count(*) FROM t1 GROUP BY log ORDER BY log}} {0 1 1 1 2 2 3 4 4 8 5 15}do_test select3-2.2 {  execsql {SELECT log, min(n) FROM t1 GROUP BY log ORDER BY log}} {0 1 1 2 2 3 3 5 4 9 5 17}do_test select3-2.3.1 {  execsql {SELECT log, avg(n) FROM t1 GROUP BY log ORDER BY log}} {0 1.0 1 2.0 2 3.5 3 6.5 4 12.5 5 24.0}do_test select3-2.3.2 {  execsql {SELECT log, avg(n)+1 FROM t1 GROUP BY log ORDER BY log}} {0 2.0 1 3.0 2 4.5 3 7.5 4 13.5 5 25.0}do_test select3-2.4 {  execsql {SELECT log, avg(n)-min(n) FROM t1 GROUP BY log ORDER BY log}} {0 0.0 1 0.0 2 0.5 3 1.5 4 3.5 5 7.0}do_test select3-2.5 {  execsql {SELECT log*2+1, avg(n)-min(n) FROM t1 GROUP BY log ORDER BY log}} {1 0.0 3 0.0 5 0.5 7 1.5 9 3.5 11 7.0}do_test select3-2.6 {  execsql {    SELECT log*2+1 as x, count(*) FROM t1 GROUP BY x ORDER BY x  }} {1 1 3 1 5 2 7 4 9 8 11 15}do_test select3-2.7 {  execsql {    SELECT log*2+1 AS x, count(*) AS y FROM t1 GROUP BY x ORDER BY y, x  }} {1 1 3 1 5 2 7 4 9 8 11 15}do_test select3-2.8 {  execsql {    SELECT log*2+1 AS x, count(*) AS y FROM t1 GROUP BY x ORDER BY 10-(x+y)  }} {11 15 9 8 7 4 5 2 3 1 1 1}do_test select3-2.9 {  catchsql {    SELECT log, count(*) FROM t1 GROUP BY 'x' ORDER BY log;  }} {1 {GROUP BY terms must not be non-integer constants}}do_test select3-2.10 {  catchsql {    SELECT log, count(*) FROM t1 GROUP BY 0 ORDER BY log;  }} {1 {GROUP BY column number 0 out of range - should be between 1 and 2}}do_test select3-2.11 {  catchsql {    SELECT log, count(*) FROM t1 GROUP BY 3 ORDER BY log;  }} {1 {GROUP BY column number 3 out of range - should be between 1 and 2}}do_test select3-2.12 {  catchsql {    SELECT log, count(*) FROM t1 GROUP BY 1 ORDER BY log;  }} {0 {0 1 1 1 2 2 3 4 4 8 5 15}}#do_test select3-2.13 {#  catchsql {#    SELECT log, count(*) FROM t1 GROUP BY 2 ORDER BY log;#  }#} {0 {0 1 1 1 2 2 3 4 4 8 5 15}}#do_test select3-2.14 {#  catchsql {#    SELECT log, count(*) FROM t1 GROUP BY count(*) ORDER BY log;#  }#} {0 {0 1 1 1 2 2 3 4 4 8 5 15}}# Cannot have a HAVING without a GROUP BY#do_test select3-3.1 {  set v [catch {execsql {SELECT log, count(*) FROM t1 HAVING log>=4}} msg]  lappend v $msg} {1 {a GROUP BY clause is required before HAVING}}# Toss in some HAVING clauses#do_test select3-4.1 {  execsql {SELECT log, count(*) FROM t1 GROUP BY log HAVING log>=4 ORDER BY log}} {4 8 5 15}do_test select3-4.2 {  execsql {    SELECT log, count(*) FROM t1     GROUP BY log     HAVING count(*)>=4     ORDER BY log  }} {3 4 4 8 5 15}do_test select3-4.3 {  execsql {    SELECT log, count(*) FROM t1     GROUP BY log     HAVING count(*)>=4     ORDER BY max(n)+0  }} {3 4 4 8 5 15}do_test select3-4.4 {  execsql {    SELECT log AS x, count(*) AS y FROM t1     GROUP BY x    HAVING y>=4     ORDER BY max(n)+0  }} {3 4 4 8 5 15}do_test select3-4.5 {  execsql {    SELECT log AS x FROM t1     GROUP BY x    HAVING count(*)>=4     ORDER BY max(n)+0  }} {3 4 5}do_test select3-5.1 {  execsql {    SELECT log, count(*), avg(n), max(n+log*2) FROM t1     GROUP BY log     ORDER BY max(n+log*2)+0, avg(n)+0  }} {0 1 1.0 1 1 1 2.0 4 2 2 3.5 8 3 4 6.5 14 4 8 12.5 24 5 15 24.0 41}do_test select3-5.2 {  execsql {    SELECT log, count(*), avg(n), max(n+log*2) FROM t1     GROUP BY log     ORDER BY max(n+log*2)+0, min(log,avg(n))+0  }} {0 1 1.0 1 1 1 2.0 4 2 2 3.5 8 3 4 6.5 14 4 8 12.5 24 5 15 24.0 41}# Test sorting of GROUP BY results in the presence of an index# on the GROUP BY column.#do_test select3-6.1 {  execsql {    SELECT log, min(n) FROM t1 GROUP BY log ORDER BY log;  }} {0 1 1 2 2 3 3 5 4 9 5 17}do_test select3-6.2 {  execsql {    SELECT log, min(n) FROM t1 GROUP BY log ORDER BY log DESC;  }} {5 17 4 9 3 5 2 3 1 2 0 1}do_test select3-6.3 {  execsql {    SELECT log, min(n) FROM t1 GROUP BY log ORDER BY 1;  }} {0 1 1 2 2 3 3 5 4 9 5 17}do_test select3-6.4 {  execsql {    SELECT log, min(n) FROM t1 GROUP BY log ORDER BY 1 DESC;  }} {5 17 4 9 3 5 2 3 1 2 0 1}do_test select3-6.5 {  execsql {    CREATE INDEX i1 ON t1(log);    SELECT log, min(n) FROM t1 GROUP BY log ORDER BY log;  }} {0 1 1 2 2 3 3 5 4 9 5 17}do_test select3-6.6 {  execsql {    SELECT log, min(n) FROM t1 GROUP BY log ORDER BY log DESC;  }} {5 17 4 9 3 5 2 3 1 2 0 1}do_test select3-6.7 {  execsql {    SELECT log, min(n) FROM t1 GROUP BY log ORDER BY 1;  }} {0 1 1 2 2 3 3 5 4 9 5 17}do_test select3-6.8 {  execsql {    SELECT log, min(n) FROM t1 GROUP BY log ORDER BY 1 DESC;  }} {5 17 4 9 3 5 2 3 1 2 0 1}# Sometimes an aggregate query can return no rows at all.#do_test select3-7.1 {  execsql {    CREATE TABLE t2(a,b);    INSERT INTO t2 VALUES(1,2);    SELECT a, sum(b) FROM t2 WHERE b=5 GROUP BY a;  }} {}do_test select3-7.2 {  execsql {    SELECT a, sum(b) FROM t2 WHERE b=5;  }} {{} {}}finish_test