?? 5--篩選負數取其絕對值之和.mht
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Subject: =?gb2312?B?yrXA/TU=?=
Date: Tue, 7 Oct 2003 01:58:16 +0800
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<HTML><HEAD><TITLE>=CA=B5=C0=FD5</TITLE>
<META content=3D"text/html; charset=3Dgb2312" http-equiv=3DContent-Type>
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<BODY bgColor=3D#00ffff text=3D#000000><FONT =
face=3D=BB=AA=CE=C4=CF=B8=BA=DA=20
size=3D2><BR><BR><BR></FONT><B><FONT color=3D#0000ff =
face=3D=BB=AA=CE=C4=CF=B8=BA=DA=20
size=3D3>=B3=CC=D0=F25=A3=BA</FONT></B><FONT =
face=3D=BB=AA=CE=C4=CF=B8=BA=DA=20
size=3D2>=C6=E4=B9=A6=C4=DC=CA=C7:=B4=D310=B8=F6=D3=D0=B7=FB=BA=C5=D7=D6=BD=
=DA=CA=FD=BE=DD=D6=D0=C8=A1=B3=F6=B8=BA=CA=FD=B2=A2=BC=C6=CB=E3=C6=E4=BE=F8=
=B6=D4=D6=B5=D6=AE=BA=CD=A3=A8=D7=D6=D0=CD),=C8=BB=BA=F3=B4=E6=B7=C5=D4=DA=
=D6=B8=B6=A8=B5=C4=C4=DA=B4=E6=D6=D0,=B6=E0=D3=E0 =20
=B5=C4=BF=D5=BC=E4=CC=EE0<BR> =
=C0=FD=C8=E7:<BR>=C4=DA=B4=E6=D6=D0=D3=D0=20
80H=A3=AC01H=A3=AC02H=A3=AC00H=A3=ACFFH=A3=AC7CH=A3=ACFEH=A3=AC7BH=A3=ACF=
DH=A3=AC81H<BR>=BD=E1=B9=FB=CE=AA=20
80H=A3=ACFFH=A3=ACFEH=A3=ACFDH=A3=AC81H=A3=AC05H=A3=AC01H=A3=AC00H=A3=AC0=
0H=A3=AC00H<BR></FONT>
<P><FONT face=3D=BB=AA=CE=C4=CF=B8=BA=DA size=3D2><BR></FONT><FONT =
face=3D"Bookman Old Style" size=3D2>DATA=20
SEGMENT<BR>SOURCE DB 80H,01H,02H,00H,0FFH,7CH,0FEH,7BH,0FDH,81H =
;</FONT><FONT=20
size=3D2>=B8=F6=CA=FD=C8=CE=D2=E2<BR></FONT><FONT face=3D"Bookman Old =
Style" size=3D2>COUNT EQU=20
$-SOURCE<BR>RESULT DB COUNT DUP (?)<BR>DATA ENDS</FONT></P>
<P><FONT size=3D2>=A3=BB</FONT><FONT face=3D"Bookman Old Style"=20
size=3D2>---------------------------------<BR>CODE=20
SEGMENT<BR> ASSUME=20
CS:CODE,DS:DATA<BR> MAIN PROC=20
FAR<BR> PUSH=20
DS<BR> XOR=20
AX,AX<BR> PUSH=20
AX<BR> MOV=20
AX,DATA<BR> MOV =
DS,AX<BR>START: MOV=20
SI,OFFSET SOURCE<BR> MOV =
DI,OFFSET=20
RESULT<BR> MOV CX,COUNT =
</FONT><FONT=20
size=3D2>=A3=BB=CA=FD=D7=E9=B8=F6=CA=FD<BR></FONT><FONT face=3D"Bookman =
Old Style"=20
size=3D2> MOV BX,0 =
</FONT><FONT=20
size=3D2>=A3=BB</FONT><FONT face=3D"Bookman Old Style" =
size=3D2>BX</FONT><FONT=20
size=3D2>=CE=AA=B8=BA=CA=FD=BC=C6=CA=FD=C6=F7<BR></FONT><FONT =
face=3D"Bookman Old Style"=20
size=3D2> MOV DX,0 =
</FONT><FONT=20
size=3D2>=A3=BB=BA=CD=BC=C4=B4=E6=C6=F7=C7=E5=C1=E3<BR></FONT><FONT =
face=3D"Bookman Old Style" size=3D2>LOP1: MOV AL,[SI]=20
</FONT><FONT size=3D2>=A3=BB=C8=A1=CA=FD=B1=C8=BD=CF<BR></FONT><FONT =
face=3D"Bookman Old Style"=20
size=3D2> CMP=20
AL,0<BR> JGE=20
LOP2<BR> MOV=20
[DI],AL<BR> NEG=20
AL<BR> MOV=20
AH,0<BR> ADD=20
DX,AX<BR> INC=20
BX<BR> INC=20
DI<BR> LOP2: INC=20
SI<BR> LOOP =
LOP1<BR> =20
MOV [DI],DX<BR> ADD DI,2<BR>DONE: MOV BYTE =
PTR=20
[DI],0 </FONT><FONT =
size=3D2>=A3=BB=CA=A3=D3=E0=B5=C4=BF=D5=BC=E4=C7=E5=C1=E3 =
<BR></FONT><FONT face=3D"Bookman Old Style"=20
size=3D2> INC BX<BR> CMP =
BX,COUNT<BR> JB DONE<BR> =
RET<BR> MAIN ENDP<BR>CODE=20
ENDS<BR> END MAIN=20
<BR><BR></FONT><FONT size=3D2>=CB=B5=C3=F7=A3=BA</FONT><FONT =
face=3D"Bookman Old Style"=20
size=3D2>1.</FONT><FONT =
size=3D2>=B1=BE=B3=CC=D0=F2=D2=D4=C9=CF=BB=FA=CD=A8=B9=FD<BR></FONT><FONT=
face=3D"Bookman Old Style"=20
size=3D2>2. </FONT><FONT =
size=3D2>=CA=FD=BE=DD=B4=AE=B5=C4=B8=F6=CA=FD=C8=CE=D2=E2</FONT></P>
<P></P></BODY></HTML>
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