?? mrandom.c
字號(hào):
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include "msp.h"
float randnu(long *iseed)
{
float z;
*iseed=2045*(*iseed)+1;
*iseed=*iseed-(*iseed/1048576)*1048576;
z=(float)((*iseed+1)/1048577.0);
return(z);
}
/*--------------------------------------------------------------------*/
void meavar(float u[],int *n,float *pum,float *puv)
{
int i,k;
*pum=0.0;
for(k=0;k<*n;k++)
*pum=*pum+u[k];
*pum=*pum/(*n);
*puv=0.0;
for(i=0;i<*n;i++)
*puv=*puv+pow((u[i]-*pum),2);
*puv=*puv/(*n-1.);
return;
}
/*---------------------------------------------------------------------
Routine mrandom : To generate the random number(pseudo-white noise).
input Parameters:
n : the random data number requested; integer .
iseed: the seed for pseudo-random data generation.it must be
initialized by main program(suggested value is ISEED=12357),
and the random number is cycled,the cycle length=1,048,576
itype: random data distribution type, see below:
itype=1: Uniform distributed,from 0.0 to 1.0
itype=2: Uniform distributed,Mean=0.0, Variance(Power) p=1.0
itype=3: Uniform distributed,Mean=0.0, Variance(Power) p=p.
itype=4: Gaussian distributed,Mean=0.0, Variance(Power) p=1.0
itype=5: Gaussian distributed,Mean=0.0, Variance(Power) p=p.
p :variance(Power) of random, only used when itype=3 or itype=5.
out parameters:
u :n dimensioned real array, data is stored in u(0) to u(n-1).
in Chapter 1
---------------------------------------------------------------------*/
void mrandom(float u[],int *n,long *piseed,int itype,float p)
{
int k,ns,ksection,ks,j;
float a,v,umean,uvari;
float *pum,*puv;
pum=&umean;
puv=&uvari;
if(itype >6 || itype <1)
return;
for(k=0;k<*n;k++)
u[k]=randnu(piseed);
if(itype==2 || itype==3)
{
meavar(u,n,pum,puv);
/* to obtain a zero mean and P-power random sequence u[k]).*/
a=12.;
if(itype==2)
p=sqrt(a);
if(itype==3)
p=sqrt(p*a);
for(k=0;k<*n;k++)
u[k]=(u[k]-umean)*p;
}
if(itype==4||itype==5)
{
/* to generate the Gaussian randow sequence u[k],k=0,1,2,...,ns-1*/
ksection=12;
ns=*n/ksection;
ks=0;
if (itype==4) p=1;
p=sqrt(p);
for(k=0;k<ns;k++)
{v=0.0;
for(j=0;j<ksection;j++)
v+=p*(u[j+ks]-.5);
u[k]=v;
ks=ks+ksection;
}
*n=ns;
}
meavar(u,n,pum,puv);
printf(" The mean of u[n]=%f\n",umean);
printf(" The variance of u[n]=%f\n",uvari);
return;
}
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