?? chp10ex3.m
字號(hào):
% (a) Solution by mesh analysis
Zs=j*12; Zm=j*4; VL=100*sqrt(3);
Z= [(Zs-Zm) -(Zs-Zm) 0
0 (Zs-Zm) -(Zs-Zm)
1 1 1 ];
V=[VL*cos(pi/6)+j*VL*sin(pi/6)
VL*cos(-pi/2)+j*VL*sin(-pi/2)
0 ];
Y=inv(Z)
Iabc=Y*V; % Line currents (Rectangular form)
Iabcp=[abs(Iabc), angle(Iabc)*180/pi] % Line currents (Polar form)
% (b) Solution by symmetrical component method
disp('Solution by Symmetrical component method' )
Z012=[Zs+2*Zm 0 0 % Symmetrical components matrix
0 Zs-Zm 0
0 0 Zs-Zm];
V012=[0; VL/sqrt(3); 0]; % Symmetrical components of phase voltages
I012=inv(Z012)*V012; % Symmetrical components of line currents
a=cos(2*pi/3)+j*sin(2*pi/3);
A=[ 1 1 1; 1 a^2 a; 1 a a^2]; % Transformation matrix
Iabc=A*I012; % Line currents (Rectangular form)
Iabcp=[abs(Iabc), angle(Iabc)*180/pi] % Line currents (Polar form)
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