function K3 = fill_K3 (B)

% for K3 the results with Karnought are:
% [ b0  1  b2  0  b4  1  b6  b7  b8  1  b10  1  b12  1  b14  b15];
% [ 1       0      1      0   0   1      1       1       1    1 ]

% fill the variables for K3 in the corresponding places
K3 = [B(1) 1 B(2) 0 B(3) 1 B(4:6) 1 B(7) 1 B(8) 1 B(9:10)];