/*  This Code is Submitted by wywcgs for Problem 1078 on 2005-03-04 at 21:32:28 */ 
#include <stdio.h>

int main()
{
    double b[10] = {0};
    int i, a[10] = {1};
    
    for(i = 1; i < 10; i++){
        a[i] = a[i-1] * i;
    }
    printf("n e\n");
    printf("- -----------\n");
    for(i = 0; i < 10; i++){
        printf("%d ", i);
        if(i == 0){
            b[0] = 1 / (double)a[0];
            printf("%.0lf\n", b[0]);
        }else if(i == 1){
            b[1] = b[0] + 1 / (double)a[1];
            printf("%.0lf\n", b[1]);
        }else if(i == 2){
            b[2] = b[1] + 1 / (double)a[2];
            printf("%.1lf\n", b[2]);
        }else{
            b[i] = b[i-1] + 1 / (double)a[i];
            printf("%.9lf\n", b[i]);
        }
    }
    
    return 0;
}