?? c26x0512.asm
字號:
.file "c2cx0512.asm"
.title "512 point DIT Radix-2, Complex FFT"
.width 120
N .set 512 ; NUMBER OF POINTS FOR FFT
******************************************************************************
* *
* 256 - POINT COMPLEX, RADIX-2 DIT FFT WITH THE TMS320C2x *
* ------------------------------------------------------- *
* *
* THE PROGRAM IS BASED ON THE BOOK 'DIGITAL SIGNAL PROCESSING APPLICATIONS' *
* BIT REVERSAL ADDRESSING MODE. *
* *
* THE PROGRAM IS A MIXTURE OF LOOPED AND STRAIGHT FORWARD CODE TO OPTIMIZE *
* CODESIZE AND EXECUTION TIME. TWO OPTIMIZATION FACTORS FOR CODESIZE AND *
* EXECUTION TIME EVALUATION ARE POSSIBLE (divid = 2 and 4). *
* *
* WRITTEN BY: MANFRED CHRIST REVISION: 1.00 5. Sept. 90 *
* *
* COPYRIGHT TEXAS INSTRUMENTS INC. 1990 *
* *
******************************************************************************
* *
* USED REGISTER: AR0..AR7, ACCU, PREG, TREG, 2 STACKLEVEL, BLOCK B2 *
* *
* COEFFICIENTS : 16 BITS (Q15 Format) SCALING: 1/2^8=1/256 *
* *
* c25/e25/e26 320c25-50 only *
* ------------- ---------------- program twiddle *
* dsp divid cycles t-cyc=100ns t_cyc=80ns words words type *
* ----- ----- ------- ------------- ---------------- ------- ----- ---- *
* e/c25 2 19,028 1,902.7 us 1,522.76 us 321 366 mp/mc *
* c26 2 16,587 1,658.7 us ------- 321 366 mp *
* e/c25 4 18,476 1,847.6 us 1,478.08 us 564 366 mp/mc *
* c26 4 16,035 1,603.5 us ------- 564 366 mp *
* *
* PROGRAMSEQUENCE: 0. INITIALISATION FOR FFT/COEFF ADD: 400H - 5..H *
* 1. INPUT NEW DATA INTO 'INPUT' ADD: 2000H - 21FFH *
* 2. CALL SUBROUTINE FFT ADD: 800H - 9..H *
* 2.1. BITREVERSAL FROM INPUT TO DATA ADD: 200H - 3FFH *
* 2.2. FFT WITH WORK SPACE DATA ADD: 200H - 3FFH *
* 3. OUTPUT THE RESULTS FROM DATA ADD: 200H - 3FFH *
* *
* INPUT DATA AT ADDRESS 2000h-21FFh: *
* ---------------------------------- *
* THE DATA ARE STORED IN 'INPUT' IN THE SEQUENCE: X(0),X(1),...,X(255) *
* Y(0),Y(1),...,Y(255) *
* *
* OUTPUT DATA AT ADDRESS 0200h-03FFh: *
* ----------------------------------- *
* THE DATA ARE STORED IN 'DATA' IN THE SEQUENCE: *
* X(0),Y(0),X(1),Y(1),... ... ,X(255),Y(255) *
******************************************************************************
* *
* THIS PROGRAM INCUDES FOLLOWING FILE: *
* ------------------------------------ *
* THE FILE 'TWIDDLES.Q15' CONSISTS OF TWIDDLE FACTORS IN Q15 FORMAT *
* THE FILE 'C2CXRAD2.MAC' macro files *
* THE FILE 'INIT-256.ASM' for initialization *
* THE FILE 'DIVID.ASM' defines the optimisazation (used in $loop repeat) *
******************************************************************************
.include divid.asm ; define optimization: 2 + 4 are tested
.include c2cxrad2.mac ; macro file
;
.def TWIDLEN,FFTLEN,TWIDSTRT,INPUT,INIT,FFT
.def STAGE1,STAGE3,STAGE4,SINES4
.sect "twiddles"
; table of twiddle factors for the FFT
TWIDSTRT .set $
.include twiddles.q15
TWIDLEN .set $-TWIDSTRT
;
INPUT .usect "input",N*2 ; input data array
BUFFER .usect "buffer",N*2 ; reserve space for bit reversal buffer
DATA .data
.space N*2*16 ; working data array
TWID1 .usect "twid1",N ; reserve space for twiddles: STAGES 4-8
TWID2 .usect "twid2",N ; reserve space for twiddles: STAGE 9
;
.include init-C26.asm
;
.sect "fftprogram"
;
; FFT CODE WITH BIT-REVERSED INPUT SAMPLES / ARP=AR3 / DP=0
;
; transfer 2*N input data from 'INPUT' to 'BUFFER'
;
FFT: lar ar3,DATAADD
lar ar0,NN ; indexregister = N
rpt #255
bldd #INPUT,*BR0+
rpt #255
bldd #INPUT+100h,*BR0+
rpt #255
bldd #INPUT+200h,*BR0+
rpt #255
bldd #INPUT+300h,*BR0+
;
; FFT CODE for STAGES 1 and 2 / ARP=AR3
;
STAGE1: lar ar0,#7 ; indexregister = 7
lar ar1,DATAADD ; pointer to DATA r1,i1
lar ar2,DATA2 ; pointer to DATA + 2 r2,i2
lar ar3,DATA4 ; pointer to DATA + 4 r3,i3
lar ar4,DATA6 ; pointer to DATA + 6 r4,i4
COMBO2X 128 ; repeat 128 times
;
; FFT CODE FOR STAGE 3 / ARP=AR2
;
STAGE3: lar ar0,#9 ; index register = 9
lar ar1,DATAADD ; ar1 -> DATA
lar ar2,DATA8 ; ar2 -> DATA+8
stage3l 64 ; repeat stage3 64 times
;
; FFT CODE FOR STAGE 4 / ARP=AR2
;
STAGE4: lar ar0,#16 ; index register = 16
sar ar0,TEMP+1 ; save ar0
lar ar1,DATAADD ; ar1 -> DATA
lar ar2,DATA16 ; ar2 -> DATA+16
lar ar6,#31 ; repeat loop4 32 times
;
loop4: lar ar3,cos4 ; start of cosine in stage 4
lar ar4,sin4 ; start of sine in stage 4
do_btfly 8 ; setup for 8 butterflies
banz loop4,*-,ar2
;
; FFT CODE FOR STAGE 5 / ARP=AR2
;
STAGE5: lar ar0,#32 ; index register = 32
sar ar0,TEMP+1 ; save ar0
lar ar1,DATAADD ; ar1 -> DATA
lar ar2,DATA32 ; ar2 -> DATA+32
lar ar6,#15 ; repeat loop5 16 times
;
loop5: lar ar3,cos5 ; start of cosine in stage 5
lar ar4,sin5 ; start of sine in stage 5
do_btfly 16 ; setup for 16 butterflies
banz loop5,*-,ar2
;
; FFT CODE FOR STAGE 6 / ARP=AR2
;
STAGE6: lar ar0,#64 ; index register = 64
sar ar0,TEMP+1 ; save ar0
lar ar1,DATAADD ; ar1 -> DATA
lar ar2,DATA64 ; ar2 -> DATA+64
lar ar6,#7 ; repeat loop6 8 times
;
loop6: lar ar3,cos6 ; start of cosine in stage 6
lar ar4,sin6 ; start of sine in stage 6
do_btfly 32 ; setup for 32 butterflies
banz loop6,*-,ar2
;
;
; FFT CODE FOR STAGE 7 / ARP=AR2
;
STAGE7: lar ar0,#128 ; index register = 128
sar ar0,TEMP+1 ; save ar0
lar ar1,DATAADD ; ar1 -> DATA
lar ar2,DATA128 ; ar2 -> DATA+128
lar ar6,#3 ; repeat loop7 4 times
;
loop7: lar ar3,cos7 ; start of cosine in stage 7
lar ar4,sin7 ; start of sine in stage 7
do_btfly 64 ; setup for 64 butterflies
banz loop7,*-,ar2
;
; FFT CODE FOR STAGE 8 / ARP=AR2
;
STAGE8: lar ar0,v256 ; index register = 256
sar ar0,TEMP+1 ; save ar0
lar ar1,DATAADD ; ar1 -> DATA
lar ar2,DATA256 ; ar2 -> DATA+256
lar ar6,#1 ; repeat loop8 2 times
;
loop8: lar ar3,cos8 ; start of cosine in stage 8
lar ar4,sin8 ; start of sine in stage 8
do_btfly 128 ; setup for 128 butterflies
banz loop8,*-,ar2
;
; FFT CODE FOR STAGE 9 / ARP=AR2
;
STAGE9: lar ar1,DATAADD ; ar1 -> DATA
lar ar2,DATA512 ; ar2 -> DATA+512
;
lar ar3,cos9 ; start of cosine in stage 9
lar ar4,sin9 ; start of sine in stage 9
; the next two loops finish the FFT
do_loops 256 ; setup for 256 butterflies
ex_btfly ; execute the butterflies
FFTLEN .set $-FFT
.end
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