?? 1987.cpp
字號:
/* This Code is Submitted by wywcgs for Problem 1987 on 2005-09-22 at 14:16:28 */
#include <stdio.h>
int main()
{
int n, m, i, f[10001];
while(scanf("%d %d", &n, &m) == 2) {
if(m == 0 && n == 0) {
return 0;
} else {
if(n < 0) {
while(n < 0) {
n += m;
}
printf("%d\n", n % m);
} else {
for(i = 0; i <= n; i++) {
if(i < 4) {
f[i] = i % m;
} else {
f[i] = (f[i-1] + f[i-3]) % m;
}
}
printf("%d\n", f[n]);
}
}
}
return 0;
}
?? 快捷鍵說明
復(fù)制代碼
Ctrl + C
搜索代碼
Ctrl + F
全屏模式
F11
切換主題
Ctrl + Shift + D
顯示快捷鍵
?
增大字號
Ctrl + =
減小字號
Ctrl + -