?? 超長整數運算（大數運算）.mht
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<UL>
<LI>C </LI></UL><PRE>void add(int *a, int *b, int *c) { <BR> int i, =
carry =3D 0; <BR><BR> for(i =3D N - 1; i >=3D 0; i--) { <BR> =
c[i] =3D a[i] + b[i] + carry; <BR> if(c[i] < 10000) <BR> =
carry =3D 0; <BR> else { // =B6i=A6=EC <BR> c[i] =
=3D c[i] - 10000; <BR> carry =3D 1; <BR> } <BR> } =
<BR>} <BR><BR>void sub(int *a, int *b, int *c) { <BR> int i, borrow =
=3D 0; <BR><BR> for(i =3D N - 1; i >=3D 0; i--) { <BR> c[i] =
=3D a[i] - b[i] - borrow; <BR> if(c[i] >=3D 0) <BR> =
borrow =3D 0; <BR> else { // =AD=C9=A6=EC <BR> c[i] =
=3D c[i] + 10000; <BR> borrow =3D 1; <BR> } <BR> } =
<BR>} <BR><BR>void mul(int *a, int b, int *c) { // b =AC=B0=AD=BC=BC=C6 =
<BR> int i, tmp, carry =3D 0; <BR><BR> for(i =3D N - 1; i =
>=3D0; i--) { <BR> tmp =3D a[i] * b + carry; <BR> c[i] =
=3D tmp % 10000; <BR> carry =3D tmp / 10000; <BR> } <BR>} =
<BR><BR>void div(int *a, int b, int *c) { // b =AC=B0=B0=A3=BC=C6 <BR> =
int i, tmp, remain =3D 0; <BR><BR> for(i =3D 0; i < N; i++) { =
<BR> tmp =3D a[i] + remain; <BR> c[i] =3D tmp / b; <BR> =
remain =3D (tmp % b) * 10000; <BR> } <BR>} <BR></PRE><BR>
<UL>
<LI>Java </LI></UL><PRE>public class BigNumber {<BR> public static =
int[] add(int[] a, int[] b) { <BR> int carry =3D 0;<BR> =
int[] c =3D new int[a.length];<BR><BR> for(int i =3D a.length - =
1; i >=3D 0; i--) { <BR> c[i] =3D a[i] + b[i] + carry; =
<BR> if(c[i] < 10000) <BR> carry =3D 0; =
<BR> else { // =B6i=A6=EC <BR> c[i] =3D c[i] - =
10000; <BR> carry =3D 1; <BR> } <BR> =
}<BR> <BR> return c;<BR> } <BR><BR> public static =
int[] sub(int[] a, int[] b) { <BR> int borrow =3D 0; <BR> =
int[] c =3D new int[a.length];<BR> <BR> for(int i =3D =
a.length - 1; i >=3D 0; i--) { <BR> c[i] =3D a[i] - b[i] - =
borrow; <BR> if(c[i] >=3D 0) <BR> borrow =
=3D 0; <BR> else { // =AD=C9=A6=EC <BR> c[i] =
=3D c[i] + 10000; <BR> borrow =3D 1; <BR> } =
<BR> }<BR> <BR> return c;<BR> } <BR><BR> =
public static int[] mul(int[] a, int b) { // b =AC=B0=AD=BC=BC=C6 <BR> =
int carry =3D 0; <BR> int[] c =3D new int[a.length];<BR> =
<BR> for(int i =3D a.length - 1; i >=3D0; i--) { <BR> =
int tmp =3D a[i] * b + carry; <BR> c[i] =3D tmp % 10000; =
<BR> carry =3D tmp / 10000; <BR> } <BR> <BR> =
return c;<BR> } <BR><BR> public static int[] div(int[] a, =
int b) { // b =AC=B0=B0=A3=BC=C6 <BR> int remain =3D 0; <BR> =
int[] c =3D new int[a.length];<BR><BR> for(int i =3D 0; i < =
a.length; i++) { <BR> int tmp =3D a[i] + remain; <BR> =
c[i] =3D tmp / b; <BR> remain =3D (tmp % b) * 10000; <BR> =
} <BR> <BR> return c;<BR> }<BR> <BR> public =
static void main(String[] args) {<BR> int[] a =3D {1234, 5678, =
9910, 1923, 1124};<BR> int[] b =3D {1234, 5678, 9910, 1923, =
1124};<BR> int[] c =3D BigNumber.add(a, b);<BR> <BR> =
for(int i =3D 0; i < c.length; i++) {<BR> =
System.out.print(c[i]);<BR> }<BR> =
System.out.println();<BR> }<BR>}</PRE><BR></DIV></DIV></BODY></HTML>
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顯示快捷鍵
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增大字號
Ctrl + =
減小字號
Ctrl + -