【問題描述】 在一個N*N的點陣中，如N=4,你現(xiàn)在站在（1，1），出口在（4，4）。你可以通過上、下、左、右四種移動方法，在迷宮內(nèi)行走，但是同一個位置不可以訪問兩次，亦不可以越界。表格最上面的一行加黑數(shù)字A[1..4]分別表示迷宮第I列中需要訪問并僅可以訪問的格子數(shù)。右邊一行加下劃線數(shù)字B[1..4]則表示迷宮第I行需要訪問并僅可以訪問的格子數(shù)。如圖中帶括號紅色數(shù)字就是一條符合條件的路線。 給定N，A[1..N] B[1..N]。輸出一條符合條件的路線，若無解，輸出NO ANSWER。（使用U，D，L，R分別表示上、下、左、右。） 2 2 1 2 （4，4） 1 （2，3） （3，3） （4，3） 3 （1，2） （2，2） 2 （1，1） 1 【輸入格式】 第一行是數(shù)m (n < 6 )。第二行有n個數(shù)，表示a[1]..a[n]。第三行有n個數(shù)，表示b[1]..b[n]。 【輸出格式】 僅有一行。若有解則輸出一條可行路線，否則輸出“NO ANSWER”。
標(biāo)簽： 點陣
上傳時間： 2014-06-21
上傳用戶：llandlu
Asp.Net探針0.90源碼（Asp.net2.0版） 探測信息如下： 服務(wù)器計算機名 http://localhost/ 服務(wù)器IP地址 127.0.0.1 服務(wù)器域名 localhost 服務(wù)器端口 80 服務(wù)器IIS版本 Microsoft-IIS/6.0 本文件所在文件夾 E:\downCode\ServerInfo\ 服務(wù)器操作系統(tǒng) Microsoft Windows NT 5.2.3790 Service Pack 1 系統(tǒng)所在文件夾 C:\WINDOWS\system32 服務(wù)器腳本超時時間 30000秒 服務(wù)器的語言種類 Chinese (People s Republic of China) .NET Framework 版本 2.050727.42 服務(wù)器當(dāng)前時間 2007-5-25 9:18:18 服務(wù)器IE版本 7.0000 服務(wù)器上次啟動到現(xiàn)在已運行 51分鐘 邏輯驅(qū)動器 A:\C:\D:\E:\F:\G:\H:\I:\ CPU 總數(shù) 2 CPU 類型 x86 Family 15 Model 3 Stepping 4, GenuineIntel 虛擬內(nèi)存 61776M 當(dāng)前程序占用內(nèi)存 6.03M Asp.net所占內(nèi)存 60.48M Asp.net所占CPU 4 當(dāng)前Session數(shù)量 0 當(dāng)前SessionID t4at4w45uh5pr455cq42gq55 當(dāng)前系統(tǒng)用戶名 NETWORK SERVICE 注意：當(dāng)前版本只支持Asp.net2.0環(huán)境
標(biāo)簽： Asp localhost 0.90 http
上傳時間： 2013-12-30
上傳用戶：evil
Mastering the Requirements Process, Second Edition, sets out an industry-proven process for gathering and verifying requirements with an eye toward today s agile development environments. In this total update of the bestselling guide, the authors show how to discover precisely what the customer wants and needs while doing the minimum requirements work according to the project s level of agility.
標(biāo)簽： industry-proven Requirements Mastering gatherin
上傳時間： 2013-12-08
上傳用戶：璇珠官人
Solve the 8-puzzle problem using A * algorithme. Input: Program reads start state and goal state and heuristic (N or S) from EightPuzzle.INP file.0 representing blank. There are 2 Heuristic: 1. N: Number of misplaced tiles 2. S: Sum of Manhattan distance of current location and target location. Format: The first line write type of heuristic (N or S). Next is the status of departing and landing status. Between 2 states of 1 line blank. See examples EightPuzzle.INP
標(biāo)簽： state algorithme Program problem
上傳時間： 2017-08-12
上傳用戶：jjj0202
實驗源代碼 //Warshall.cpp #include<stdio.h> void warshall(int k,int n) { int i , j, t; int temp[20][20]; for(int a=0;a<k;a++) { printf("請輸入矩陣第%d 行元素:",a); for(int b=0;b<n;b++) { scanf ("%d",&temp[a][b]); } } for(i=0;i<k;i++){ for( j=0;j<k;j++){ if(temp[ j][i]==1) { for(t=0;t<n;t++) { temp[ j][t]=temp[i][t]||temp[ j][t]; } } } } printf("可傳遞閉包關(guān)系矩陣是:\n"); for(i=0;i<k;i++) { for( j=0;j<n;j++) { printf("%d", temp[i][ j]); } printf("\n"); } } void main() { printf("利用 Warshall 算法求二元關(guān)系的可傳遞閉包\n"); void warshall(int,int); int k , n; printf("請輸入矩陣的行數(shù) i: "); scanf("%d",&k); 四川大學(xué)實驗報告 printf("請輸入矩陣的列數(shù) j: "); scanf("%d",&n); warshall(k,n); }
上傳時間： 2016-06-27
上傳用戶：梁雪文以
Fire and Fury。 This article is about the 2018 book. For other uses, see Fire and Fury (disambiguation). The title refers to a quote by Trump about the conflict with North Korea. The book became a New York Times number one bestseller.Fire and Fury: Inside the Trump White House is a 2018 book by Michael Wolff which details the behavior of U.S. President Donald Trump and the staff of his 2016 presidential campaign and White House. The book highlights descriptions of Trump's behavior, chaotic interactions among senior White House staff, and derogatory comments about the Trump family by former White House Chief StrategistSteve Bannon. Trump is depicted as being held in low regard by his White House staff, leading Wolff to state that "100% of the people around him" believe Trump is unfit for office.[1] Reviewers generally accepted Wolff's portrait of a dysfunctional Trump administration, but were skeptical of many of the book's most controversial claims.
上傳時間： 2018-02-26
上傳用戶：Yoobaobao
This article is about the 2018 book. For other uses, see Fire and Fury (disambiguation). The title refers to a quote by Trump abot the conflict with North Korea. The book became a New York Times number one bestseller.Fire and Fury: Inside the Trump White House is a 2018 book by Michael Wolff which details the behavior of U.S. President Donald Trump and the staff of his 2016 presidential campaign and White House. The book highlights descriptions of Trump's behavior, chaotic interactions among senior White House staff, and derogatory comments about the Trump family by former White House Chief StrategistSteve Bannon. Trump is depicted as being held in low regard by his White House staff, leading Wolff to state that "100% of the people around him" believe Trump is unfit for office.[1] Reviewers generally accepted Wolff's portrait of a dysfunctional Trump administration, but were skeptical of many of the book's most controversial claims.
上傳時間： 2018-02-26
上傳用戶：Yoobaobao
#include "iostream" using namespace std; class Matrix { private: double** A; //矩陣A double *b; //向量b public: int size; Matrix(int ); ~Matrix(); friend double* Dooli(Matrix& ); void Input(); void Disp(); }; Matrix::Matrix(int x) { size=x; //為向量b分配空間并初始化為0 b=new double [x]; for(int j=0;j<x;j++) b[j]=0; //為向量A分配空間并初始化為0 A=new double* [x]; for(int i=0;i<x;i++) A[i]=new double [x]; for(int m=0;m<x;m++) for(int n=0;n<x;n++) A[m][n]=0; } Matrix::~Matrix() { cout<<"正在析構(gòu)中~~~~"<<endl; delete b; for(int i=0;i<size;i++) delete A[i]; delete A; } void Matrix::Disp() { for(int i=0;i<size;i++) { for(int j=0;j<size;j++) cout<<A[i][j]<<" "; cout<<endl; } } void Matrix::Input() { cout<<"請輸入A:"<<endl; for(int i=0;i<size;i++) for(int j=0;j<size;j++){ cout<<"第"<<i+1<<"行"<<"第"<<j+1<<"列:"<<endl; cin>>A[i][j]; } cout<<"請輸入b:"<<endl; for(int j=0;j<size;j++){ cout<<"第"<<j+1<<"個:"<<endl; cin>>b[j]; } } double* Dooli(Matrix& A) { double *Xn=new double [A.size]; Matrix L(A.size),U(A.size); //分別求得U，L的第一行與第一列 for(int i=0;i<A.size;i++) U.A[0][i]=A.A[0][i]; for(int j=1;j<A.size;j++) L.A[j][0]=A.A[j][0]/U.A[0][0]; //分別求得U，L的第r行，第r列 double temp1=0,temp2=0; for(int r=1;r<A.size;r++){ //U for(int i=r;i<A.size;i++){ for(int k=0;k<r-1;k++) temp1=temp1+L.A[r][k]*U.A[k][i]; U.A[r][i]=A.A[r][i]-temp1; } //L for(int i=r+1;i<A.size;i++){ for(int k=0;k<r-1;k++) temp2=temp2+L.A[i][k]*U.A[k][r]; L.A[i][r]=(A.A[i][r]-temp2)/U.A[r][r]; } } cout<<"計算U得:"<<endl; U.Disp(); cout<<"計算L的:"<<endl; L.Disp(); double *Y=new double [A.size]; Y[0]=A.b[0]; for(int i=1;i<A.size;i++ ){ double temp3=0; for(int k=0;k<i-1;k++) temp3=temp3+L.A[i][k]*Y[k]; Y[i]=A.b[i]-temp3; } Xn[A.size-1]=Y[A.size-1]/U.A[A.size-1][A.size-1]; for(int i=A.size-1;i>=0;i--){ double temp4=0; for(int k=i+1;k<A.size;k++) temp4=temp4+U.A[i][k]*Xn[k]; Xn[i]=(Y[i]-temp4)/U.A[i][i]; } return Xn; } int main() { Matrix B(4); B.Input(); double *X; X=Dooli(B); cout<<"~~~~解得:"<<endl; for(int i=0;i<B.size;i++) cout<<"X["<<i<<"]:"<<X[i]<<" "; cout<<endl<<"呵呵呵呵呵"; return 0; }
標(biāo)簽： 道理特分解法
上傳時間： 2018-05-20
上傳用戶：Aa123456789
In case you haven’t noticed, multimedia communication over IP and wireless net- works is exploding. Applications such as BitTorrent, used primarily for video downloads, now take up the lion’s share of all traffic on the Internet. Music file sharing, once on the legal cutting edge of massive copyright infringement on col- lege campuses around the world, has moved into the mainstream with signifi- cant legal downloads of music and video to devices such as the iPod and nu- merous other portable media players.
標(biāo)簽： Multimedia Over IP
上傳時間： 2020-05-31
上傳用戶：shancjb
Having dealt with in-depth analysis of SS#7, GSM and GPRS networks I started to monitor UTRAN interfaces approximately four years ago. Monitoring interfaces means decoding the data captured on the links and analysing how the different data segments and messages are related to each other. In general I wanted to trace all messages belonging to a single call to prove if the network elements and protocol entities involved worked fine or if there had been failures or if any kind of suspicious events had influenced the normal call proceeding or the call’s quality of service. Cases showing normal network behaviour have been documented in Kreher and Ruedebusch (UMTS Signaling. John Wiley & Sons, Ltd, 2005), which provides examples for technical experts investigating call flows and network procedures.
標(biāo)簽： Performance Measurement Practical Guide UMTS
上傳時間： 2020-06-01
上傳用戶：shancjb
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