This example implements a gameport translator on the PIC16C765. The firmware translates a gaming device plugged into the gameport to a USB gaming device. The firmware is set up to translate the DexxaTM eight-button gamepad. Changes to the firmware will be necessary for a different gaming device.
標(biāo)簽： implements translator translates gameport
上傳時間： 2015-04-26
上傳用戶：yyq123456789
DSP音頻處理示例The benefits of real-time analysis provided by DSP/BIOS are often required in programs that were engineered without it. When the program is not built from the ground up using the DSP/BIOS kernel and real-time analysis features, the lack of familiarity prevents engineers from reaping the benefits of this very powerful tool set, especially in the final stage of development when real-time analysis is needed most. This application note provides an example of the necessary steps required to utilize DSP/BIOS features in order to bring these solutions to bear in an existing application.
標(biāo)簽： DSP real-time benefits analysis
上傳時間： 2014-01-06
上傳用戶：003030
The Art of Assembly Language Amazing! You’re actually reading this. That puts you into one of three categories: a student who is being forced to read this stuff for a class, someone who picked up this book by accident (probably because you have yet to be indoctrinated by the world at large), or one of the few who actually have an interest in learning assembly language.
標(biāo)簽： Assembly Language actually Amazing
上傳時間： 2015-04-30
上傳用戶：asddsd
DM9000AE的中文手冊。很難得得哦。LOCAL BUS芯片現(xiàn)推薦一款DM9000AE網(wǎng)卡芯片，其基本特性是48PIN，10/100MLOCAL-BUS interface，工作模式8/16bit, 有AUTO－Mdix(自動翻轉(zhuǎn)）、TCP/Ip加速（check sum offload)減輕CPU負(fù)擔(dān)，提高整機(jī)效能，20ns響應(yīng)時間。2.5V/3.3V低功耗。廣泛應(yīng)用在IPTV、IPSETBOX、VOD、IPCAMERA、IPVIDEOPHONE等產(chǎn)品.
上傳時間： 2015-05-02
上傳用戶：dyctj
21天學(xué)會用JAVA開發(fā)網(wǎng)絡(luò)游戲 書籍語言： 簡體中文 書籍類型： 程序設(shè)計 授權(quán)方式： 免費(fèi)軟件 書籍大小： 287 KB 書籍等級： 整理時間： 2004-11-3 20:41:10 With all of the media attention that is focused on the Internet and the World Wide Web, figuring out exactly what they are all about is sometimes difficult. Are they just a neat new way to market products or will they truly offer us a new medium of communication that will someday surpass even televisions and telephones? The answer is, who knows? Unfortunately, the ultimate use for the Internet is still unknown. This is because it is still in such a state of flux that it s pretty much impossible to accurately predict where it will end up. However, you can look at the evidence of what is there now and gain some insight into what the Internet might become, at least in terms of games.
上傳時間： 2013-12-20
上傳用戶：天誠24
Although there has been a lot of AVL tree libraries available now, nearly all of them are meant to work in the random access memory(RAM). Some of them do provide some mechanism for dumping the whole tree into a file and loading it back to the memory in order to make data in that tree persistent. It serves well when there s just small amount of data. When the tree is somewhat bigger, the dumping/loading process could take a lengthy time and makes your mission-critical program less efficient. How about an AVL tree that can directly use the disk for data storage ? If there s something like that, we won t need to read through the whole tree in order to pick up just a little bit imformation(a node), but read only the sectors that are neccssary for locating a certain node and the sectors in which that node lies. This is my initial motivation for writing a storage-media independent AVL Tree. However, as you step forth, you would find that it not only works fine with disks but also fine with memorys, too.
標(biāo)簽： available libraries Although nearly
上傳時間： 2014-01-22
上傳用戶：zhoujunzhen
數(shù)字運(yùn)算，判斷一個數(shù)是否接近素數(shù) A Niven number is a number such that the sum of its digits divides itself. For example, 111 is a Niven number because the sum of its digits is 3, which divides 111. We can also specify a number in another base b, and a number in base b is a Niven number if the sum of its digits divides its value. Given b (2 <= b <= 10) and a number in base b, determine whether it is a Niven number or not. Input Each line of input contains the base b, followed by a string of digits representing a positive integer in that base. There are no leading zeroes. The input is terminated by a line consisting of 0 alone. Output For each case, print "yes" on a line if the given number is a Niven number, and "no" otherwise. Sample Input 10 111 2 110 10 123 6 1000 8 2314 0 Sample Output yes yes no yes no
上傳時間： 2015-05-21
上傳用戶：daguda
ITU-T Recommendation V.90 98年9月版本 A DIGITAL MODEM AND ANALOGUE MODEM PAIR FOR USE ON THE PUBLIC SWITCHED TELEPHONE NETWORK (PSTN) AT DATA SIGNALLING RATES OF UP TO 56 000 bit/s DOWNSTREAM AND UP TO 33 600 bit/s UPSTREAM
標(biāo)簽： MODEM Recommendation ANALOGUE DIGITAL
上傳時間： 2014-01-17
上傳用戶：hn891122
MFC Black Book Introduction: Are you an MFC programmer? Good. There are two types of MFC programmers. What kind are you? The first kind are the good programmers who write programs that conform to the way MFC wants you to do things. The second bunch are wild-eyed anarchists who insist on getting things done their way. Me, I’m in the second group. If you are in the same boat (or would like to be) this book is for you. This book won’t teach you MFC—not in the traditional sense. You should pick it up with a good understanding of basic MFC programming and a desire to do things differently. This isn’t a Scribble tutorial (although I will review some fundamentals in the first chapter). You will learn how to wring every drop from your MFC programs. You’ll discover how to use, abuse, and abandon the document/view architecture. If you’ve ever wanted custom archives, you’ll find that, too.
標(biāo)簽： MFC Introduction programmer programme
上傳時間： 2015-05-30
上傳用戶：youke111
某幼兒園按如下方法依次給A，B，C，D，E五個小孩發(fā)糖果。將全部糖果的一半再加二分之一塊糖果發(fā)給第一個小孩；將剩下糖果的三分之一再加三分之一塊糖果發(fā)給第二個小孩；將剩下糖果的四分之一再加四分之一塊糖果發(fā)給第三個小孩；將剩下糖果的五分之一再加五分之一塊糖果發(fā)給第四個小孩；將最后剩下的11塊糖果發(fā)給第五個小孩。每個小孩得到的糖果數(shù)均為整數(shù)。試確定原來共有多少塊糖果？每個小孩各得到多少塊糖果？ 要求結(jié)果的輸出格式為 sum＝糖果總數(shù) xa＝A得到的糖果數(shù) xb＝B得到的糖果數(shù) xc＝C得到的糖果數(shù) xd＝D得到的糖果數(shù) xe＝E得到的糖果數(shù)
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上傳時間： 2015-06-02
上傳用戶：葉山豪
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