[輸入]
圖的頂點個數N，圖中頂點之間的關系及起點A和終點B
[輸出]
若A到B無路徑，則輸出“There is no path” 否則輸出A到B路徑上個頂點
[存儲結構]
圖采用鄰接矩陣的方式存儲。
[算法的基本思想]
采用廣度優先搜索的方法，從頂點A開始，依次訪問與A鄰接的頂點VA1,VA2,...,VAK, 訪問遍之后,若沒有訪問B，則繼續訪問與VA1鄰接的頂點VA11,VA12,...,VA1M，再訪問與VA2鄰接頂點...，如此下去，直至找到B，最先到達B點的路徑，一定是邊數最少的路徑。實現時采用隊列記錄被訪問過的頂點。每次訪問與隊頭頂點相鄰接的頂點，然后將隊頭頂點從隊列中刪去。若隊空，則說明到不存在通路。在訪問頂點過程中，每次把當前頂點的序號作為與其鄰接的未訪問的頂點的前驅頂點記錄下來，以便輸出時回溯。
#include<stdio.h>
int number //隊列類型
typedef struct{
int q[20]
This application report describes the use of Timer_A3 to decode RC5 and SIRC TV IR remote control signals. The decoder described in this report is interrupt-driven and operates a background function using specific features the Timer_A3. Only a small portion of the MSP430 CPU?s nonreal-time resources is used. Specific hardware bit-latching capabilities of the Timer_A3 module are used for real-time decoding of the IR data signal, independent
and asynchronous to the CPU. CPU activity and power consumption are kept to an absolute minimum level. The Timer_A3 decoder implementation also allows other tasks to occur simultaneously if required. The solutions provided are written specifically for MSP430x11x(1) and MSP430x12x derivatives, but can be adapted to any other MSP430 incorporating Timer_A3.
電視遙控器設計基於MSP430
the calculator s usage!
after you have inputed 2 operators,choose + - * / function!
But the only situation I did t deal with is that
when you choos + fuction ,and the operaters signs is like this
-A+B,just turn it to B-A!
圖的深度遍歷，輸出結果為（紅色為鍵盤輸入的數據，權值都置為1）：
輸入頂點數和弧數:8 9
輸入8個頂點.
輸入頂點0:a
輸入頂點1:b
輸入頂點2:c
輸入頂點3:d
輸入頂點4:e
輸入頂點5:f
輸入頂點6:g
輸入頂點7:h
輸入9條弧.
輸入弧0:a b 1
輸入弧1:b d 1
輸入弧2:b e 1
輸入弧3:d h 1
輸入弧4:e h 1
輸入弧5:a c 1
輸入弧6:c f 1
輸入弧7:c g 1
輸入弧8:f g 1
深度優先遍歷: a b d h e c f g
程序結束.
