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汽車(chē)記錄儀

  • Fortran - Tóm tắ t nộ i dung mô n họ c Các khái niệ m và yế u tố

    Fortran - Tóm tắ t nộ i dung mô n họ c Các khái niệ m và yế u tố trong ngô n ngữ lậ p trình FORTRAN. Các câ u lệ nh củ a ngô n ngữ FORTRAN. Cơ bả n về chư ơ ng chư ơ ng dị ch và mô i trư ờ ng lậ p trình DIGITAL Visual Fortran. Viế t và chạ y các chư ơ ng trình cho các bài toán đ ơ n giả n bằ ng ngô n ngữ FORTRAN.

    標簽: Fortran 7855 7897 7885

    上傳時間: 2013-12-25

    上傳用戶:songrui

  • This manual describes SAMSUNG s S3C2410X 16/32-bit RISC microprocessor. This product is designed to

    This manual describes SAMSUNG s S3C2410X 16/32-bit RISC microprocessor. This product is designed to provide hand-held devices and general applications with cost-effective, low-power, and high-performance microcontroller solution in small die size. To reduce total system cost, the S3C2410X includes the following components separate 16KB Instruction and 16KB Data Cache, MMU to handle virtual memory management, LCD Controller (STN & TFT), NAND Flash Boot Loader, System Manager (chip select logic and SDRAM Controller), 3-ch UART, 4-ch DMA, 4-ch Timers with PWM, I/O Ports, RTC, 8-ch 10-bit ADC and Touch Screen Interface, IIC-BUS Interface, IIS-BUS Interface, USB Host, USB Device, SD Host & Multi-Media Card Interface, 2-ch SPI and PLL for clock generation.

    標簽: This microprocessor describes S3C2410X

    上傳時間: 2014-01-11

    上傳用戶:shizhanincc

  • 由TI-28xx範例程式

    由TI-28xx範例程式,更改TI到可以Complete,把缺的資料放入和更改記憶體時序

    標簽: TI 28 xx 程式

    上傳時間: 2017-09-06

    上傳用戶:cylnpy

  • 16進制轉十進制

    DATAS SEGMENT w dw 0 keybuf db 255      db 0      db 255 dup(0)      ;定義鍵盤輸入需要的緩沖區 DATAS ENDS STACKS SEGMENT db 200 dup(?) STACKS ENDS CODES SEGMENT ASSUME CS:CODES,DS:DATAS,SS:STACKS START: MOV AX,DATAS MOV DS,AX mov dx,offset keybuf     ;用0a號功能,輸入一個字符串 mov ah,0ah               ;用回車結束 int 21h mov dl,0ah               ;再進行換行,以便在下一行顯示轉換后的字符串  mov ah,2     int 21h ;  push ax ;   push dx ;      mov dl,cl ;     mov ah,02 ;     int 21h   ;   pop dx ;  pop ax mov bx,offset keybuf+1   ;取出字符串的字符個數,作為循環的次數 mov cl,[bx] mov ch,0     mov ax,0             again:  inc bx mov ax,[w] push bx mov bx,16 mul bx pop bx            ;是小寫字母,則轉換為大寫字母 mov [w],ax mov dl,[bx]             ;取出一個字符, cmp dl,'9' jbe lab1 cmp dl,'F' jbe lab2 sub dl,32 lab2: sub dl ,07h lab1:  sub dl,30h add [w],dx  loop again   mov ax,[w]  mov bx,-1 push bx mov bx,10 lab3 :mov dx,0 div bx  push dx cmp ax,0 jnz lab3 lab5: pop dx cmp dx,-1 jz lab4 add dl,30h mov ah,02 int 21h        jmp  lab5            ;循環,處理完整個字符串 lab4:  MOV AH,4CH INT 21H CODES ENDS END START

    標簽: 匯編

    上傳時間: 2015-04-02

    上傳用戶:wcc0310

  • Boost C++ Libraries 1.35.0

    Boost C++ Libraries Free peer-reviewed portable C++ source libraries Boost C++ Libraries 基本上是一個免費的 C++ 的跨平臺函式庫集合,基本上應該可以把它視為 C++ STL 的功能再延伸;他最大的特色在於他是一個經過「同行評審」(peer review,可參考維基百科)、開放原始碼的函式庫,而且有許多 Boost 的函式庫是由 C++ 標準委員會的人開發的,同時部分函式庫的功能也已經成為 C++ TR1 (Technical Report 1,參考維基百科)、TR2、或是 C++ 0x 的標準了。 它的官方網站是:http://www.boost.org/,包含了 104 個不同的 library;由於他提供的函式庫非常地多,的內容也非常地多元,根據官方的分類,大致上可以分為下面這二十類: 字串和文字處理(String and text processing) 容器(Containers) Iterators 演算法(Algorithms) Function objects and higher-order programming 泛型(Generic Programming) Template Metaprogramming Preprocessor Metaprogramming Concurrent Programming 數學與數字(Math and numerics) 正確性與測試(Correctness and testing) 資料結構(Data structures) 影像處理(Image processing) 輸入、輸出(Input/Output) Inter-language support 記憶體(Memory) 語法分析(Parsing) 程式介面(Programming Interfaces) 其他雜項 Broken compiler workarounds 其中每一個分類,又都包含了一個或多個函式庫,可以說是功能相當豐富。

    標簽: Boost C++ Libraries

    上傳時間: 2015-05-15

    上傳用戶:fangfeng

  • 鍋爐給水水位自動控制系統

    采用串級三沖量給水控制系統控制汽包水位,使其平穩運行,并通過MATLAB仿真,證明所設計的系統可以很好的克服系統的內外擾動,實現汽包鍋爐水位控制的要求。

    標簽: 單片機 設計

    上傳時間: 2015-05-17

    上傳用戶:yubs899

  • msp430

    msp430The LDC1312 and LDC1314 are 2- and 4-channel, 1? Easy-to-use – minimal configuration required 12-bit inductance to digital converters (LDCs) for ? Measure up to 4 sensors with one IC inductive sensing solutions. With multiple channels ? Multiple channels support environmental and and support for remote sensing, the LDC1312 and aging compensation LDC1314 enable the performance and reliability benefits of inductive sensing to be realized at minimal? Multi-channel remote sensing provides lowest cost and power. The products are easy to use, onlysystem cost requiring that the sensor frequency be within 1 kHz ? Pin-compatible medium and high-resolution and 10 MHz to begin sensing. The wide 1 kHz to 10 options MHz sensor frequency range also enables use of very small PCB coils, further reducing sensing– LDC1312/4: 2/4-ch 12-bit LDC solution cost and size.– LDC1612/4: 2/4-ch 28

    標簽: msp 430

    上傳時間: 2016-07-22

    上傳用戶:tongmoonsky

  • pads2005破解

    1.安裝Daemon Tools(虛擬光碟軟體),用Daemon Tools去開啟PADS2005.BIN,進行安裝. 2.將PADS2005-CRACK目錄複製到硬碟,刪除原先的LICENSE.TXT,執行MentorKG.exe,產生一個License.txt文件,用這個新License.txt去注冊就ok啦 

    標簽: pads 2005 破解

    上傳時間: 2016-12-16

    上傳用戶:BENLEEYM5111

  • 學生成績查詢

    #include "string.h" #include "ctype.h" #include "stdio.h" search(char pd[]) {FILE *fp; int time=0,i=0,j=0,add[80],k=0,m; char *ch, str[900]; m=strlen(pd); if((fp=fopen("haha.txt","r"))==NULL) { printf("Cannot open this file\n"); exit(0); } for(;!feof(fp);i++) { str[i]=fgetc(fp); if(tolower(str[i])==tolower(pd[k])) {k++; if(k==m) if(!isalpha(i-m)&&!isalpha((str[i++]=fgetc(fp)))) { time++; add[j]=i-m+1; j++; k=0; } else k=0; } } if(time) { printf("The time is:%d\n",time); printf("The adders is:\n"); for(i=0;i

    標簽: 查詢學會少年宮

    上傳時間: 2016-12-29

    上傳用戶:767483511

  • 學生成績管理啊

    #include "string.h" #include "ctype.h" #include "stdio.h" search(char pd[]) {FILE *fp;  int time=0,i=0,j=0,add[80],k=0,m;  char *ch,  str[900];  m=strlen(pd);  if((fp=fopen("haha.txt","r"))==NULL)  {   printf("Cannot open this file\n");   exit(0);  } for(;!feof(fp);i++)  {  str[i]=fgetc(fp);   if(tolower(str[i])==tolower(pd[k]))    {k++;     if(k==m)     if(!isalpha(i-m)&&!isalpha((str[i++]=fgetc(fp))))     {      time++;      add[j]=i-m+1;      j++;      k=0;     }     else k=0;   }  }   if(time)  {   printf("The time is:%d\n",time);   printf("The adders is:\n");   for(i=0;i<j;i++)   printf("%5d",add[i]);   if(i%5==0)   printf("\n");   getch();   fclose(fp);   }   else   printf("Sorry!Cannot find the word(^_^)"); } main() { char pd[10],choose='y'; int flag=1;     while(flag)    {printf("In put the word you want to seqarch:");     scanf("%s",pd);     search(strlwr(pd));     printf("\nWould you want to continue?(Y/N):");     getchar();     scanf("%c",&choose);     if((tolower(choose))=='n')     flag=0;     else flag=1;    }   printf("Thanks for your using!Bye-bye!\n");   getch(); }

    標簽: 學生專用

    上傳時間: 2016-12-29

    上傳用戶:767483511

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