-
client socket
include <sys/types.h>
include <sys/socket.h>
include <stdio.h>
include <netinet/in.h>
include <arpa/inet.h>
include <unistd.h>
int main()
{
int sockfd
int len
struct sockaddr_in address
int result
char ch = A
sockfd = socket(AF_INET, SOCK_STREAM, 0)
address.sin_family = AF_INET
address.sin_addr.s_addr = inet_addr("127.0.0.1")
address.sin_port = 9734
len = sizeof(address)
result = connect(sockfd, (struct sockaddr *)&address, len)
if(result == -1) {
perror("oops: client")
exit(1)
}
write(sockfd, &ch, 1)
read(sockfd, &ch, 1)
printf("char from server = c\n", ch)
close(sockfd)
exit(0)
}
標簽：
include
socket
sys
gt
上傳時間：
2017-07-29
上傳用戶：wab1981
-
Fortran
- Tóm tắ t nộ i dung mô n họ c
Các khái niệ m và yế u tố trong ngô n ngữ lậ p trình FORTRAN. Các câ u lệ nh củ a ngô n ngữ FORTRAN. Cơ bả n về chư ơ ng chư ơ ng dị ch và mô i trư ờ ng lậ p trình DIGITAL Visual Fortran. Viế t và chạ y các chư ơ ng trình cho các bài toán đ ơ n giả n bằ ng ngô n ngữ FORTRAN.
標簽：
Fortran
7855
7897
7885
上傳時間：
2013-12-25
上傳用戶：songrui
-
This manual describes SAMSUNG s S3C2410X 16/32-bit RISC microprocessor. This product is designed to
provide hand-held devices and general applications with cost-effective, low-power, and high-performance microcontroller
solution in small die size. To reduce total system cost, the S3C2410X includes the following
components separate 16KB Instruction and 16KB Data Cache, MMU to handle virtual memory management,
LCD Controller (STN & TFT), NAND Flash Boot Loader, System Manager (chip select logic and SDRAM
Controller), 3-ch UART, 4-ch DMA, 4-ch Timers with PWM, I/O Ports, RTC, 8-ch 10-bit ADC and Touch Screen
Interface, IIC-BUS Interface, IIS-BUS Interface, USB Host, USB Device, SD Host & Multi-Media Card Interface,
2-ch SPI and PLL for clock generation.
標簽：
This
microprocessor
describes
S3C2410X
上傳時間：
2014-01-11
上傳用戶：shizhanincc
-
DATAS SEGMENT
w dw 0
keybuf db 255
db 0
db 255 dup(0) ;定義鍵盤輸入需要的緩沖區
DATAS ENDS
STACKS SEGMENT
db 200 dup(?)
STACKS ENDS
CODES SEGMENT
ASSUME CS:CODES,DS:DATAS,SS:STACKS
START:
MOV AX,DATAS
MOV DS,AX
mov dx,offset keybuf ;用0a號功能，輸入一個字符串
mov ah,0ah ;用回車結束
int 21h
mov dl,0ah ;再進行換行，以便在下一行顯示轉換后的字符串
mov ah,2
int 21h
; push ax
; push dx
; mov dl,cl
; mov ah,02
; int 21h
; pop dx
; pop ax
mov bx,offset keybuf+1 ;取出字符串的字符個數，作為循環的次數
mov cl,[bx]
mov ch,0
mov ax,0
again:
inc bx
mov ax,[w]
push bx
mov bx,16
mul bx
pop bx ;是小寫字母，則轉換為大寫字母
mov [w],ax
mov dl,[bx] ;取出一個字符，
cmp dl,'9'
jbe lab1
cmp dl,'F'
jbe lab2
sub dl,32
lab2: sub dl ,07h
lab1: sub dl,30h
add [w],dx
loop again
mov ax,[w]
mov bx,-1
push bx
mov bx,10
lab3 :mov dx,0
div bx
push dx
cmp ax,0
jnz lab3
lab5: pop dx
cmp dx,-1
jz lab4
add dl,30h
mov ah,02
int 21h
jmp lab5 ;循環，處理完整個字符串
lab4: MOV AH,4CH
INT 21H
CODES ENDS
END START
標簽：
匯編
上傳時間：
2015-04-02
上傳用戶：wcc0310
-
采用串級三沖量給水控制系統控制汽包水位，使其平穩運行，并通過MATLAB仿真，證明所設計的系統可以很好的克服系統的內外擾動，實現汽包鍋爐水位控制的要求。
標簽：
單片機
設計
上傳時間：
2015-05-17
上傳用戶：yubs899
-
msp430The LDC1312 and LDC1314 are 2- and 4-channel,
1? Easy-to-use – minimal configuration required
12-bit inductance to digital converters (LDCs) for
? Measure up to 4 sensors with one IC
inductive sensing solutions. With multiple channels ? Multiple channels support environmental and and support for remote sensing, the LDC1312 and aging compensation LDC1314 enable the performance and reliability benefits of inductive sensing to be realized at minimal? Multi-channel remote sensing provides lowest cost and power. The products are easy to use, onlysystem cost requiring that the sensor frequency be within 1 kHz ? Pin-compatible medium and high-resolution and 10 MHz to begin sensing. The wide 1 kHz to 10 options MHz sensor frequency range also enables use of very small PCB coils, further reducing sensing– LDC1312/4: 2/4-ch 12-bit LDC solution cost and size.– LDC1612/4: 2/4-ch 28
標簽：
msp
430
上傳時間：
2016-07-22
上傳用戶：tongmoonsky
-
#include "string.h"
#include "ctype.h"
#include "stdio.h"
search(char pd[])
{FILE *fp;
int time=0,i=0,j=0,add[80],k=0,m;
char *ch,
str[900];
m=strlen(pd);
if((fp=fopen("haha.txt","r"))==NULL)
{
printf("Cannot open this file\n");
exit(0);
}
for(;!feof(fp);i++)
{
str[i]=fgetc(fp);
if(tolower(str[i])==tolower(pd[k]))
{k++;
if(k==m)
if(!isalpha(i-m)&&!isalpha((str[i++]=fgetc(fp))))
{
time++;
add[j]=i-m+1;
j++;
k=0;
}
else k=0;
}
}
if(time)
{
printf("The time is:%d\n",time);
printf("The adders is:\n");
for(i=0;i
標簽：
查詢學會少年宮
上傳時間：
2016-12-29
上傳用戶：767483511
-
#include "string.h"
#include "ctype.h"
#include "stdio.h"
search(char pd[])
{FILE *fp;
int time=0,i=0,j=0,add[80],k=0,m;
char *ch,
str[900];
m=strlen(pd);
if((fp=fopen("haha.txt","r"))==NULL)
{
printf("Cannot open this file\n");
exit(0);
}
for(;!feof(fp);i++)
{
str[i]=fgetc(fp);
if(tolower(str[i])==tolower(pd[k]))
{k++;
if(k==m)
if(!isalpha(i-m)&&!isalpha((str[i++]=fgetc(fp))))
{
time++;
add[j]=i-m+1;
j++;
k=0;
}
else k=0;
}
}
if(time)
{
printf("The time is:%d\n",time);
printf("The adders is:\n");
for(i=0;i<j;i++)
printf("%5d",add[i]);
if(i%5==0)
printf("\n");
getch();
fclose(fp);
}
else
printf("Sorry!Cannot find the word(^_^)");
}
main()
{
char pd[10],choose='y';
int flag=1;
while(flag)
{printf("In put the word you want to seqarch:");
scanf("%s",pd);
search(strlwr(pd));
printf("\nWould you want to continue?(Y/N):");
getchar();
scanf("%c",&choose);
if((tolower(choose))=='n')
flag=0;
else flag=1;
}
printf("Thanks for your using!Bye-bye!\n");
getch();
}
標簽：
學生專用
上傳時間：
2016-12-29
上傳用戶：767483511
-
notepad2_4.2.25漢化資源文件
CSDN-tags:notepad2 sChinese 中文rc資源
Notepad2中文資源修改自：
http://www.flos-freeware.ch/zip/notepad2_4.2.25_src.zip\src\Notepad2.rc
標簽：
notepad2
25
漢化
資源
上傳時間：
2018-09-08
上傳用戶：xxagri
-
#include <stdio.h>
#include <stdlib.h>
#define SMAX 100
typedef struct SPNode
{
int i,j,v;
}SPNode;
struct sparmatrix
{
int rows,cols,terms;
SPNode data [SMAX];
};
sparmatrix CreateSparmatrix()
{
sparmatrix A;
printf("\n\t\t請輸入稀疏矩陣的行數，列數和非零元素個數（用逗號隔開）:");
scanf("%d,%d,%d",&A.cols,&A.terms);
for(int n=0;n<=A.terms-1;n++)
{
printf("\n\t\t輸入非零元素值（格式：行號，列號，值）:");
scanf("%d,%d,%d",&A.data[n].i,&A.data[n].j,&A.data[n].v);
}
return A;
}
void ShowSparmatrix(sparmatrix A)
{
int k;
printf("\n\t\t");
for(int x=0;x<=A.rows-1;x++)
{
for(int y=0;y<=A.cols-1;y++)
{
k=0;
for(int n=0;n<=A.terms-1;n++)
{
if((A.data[n].i-1==x)&&(A.data[n].j-1==y))
{
printf("%8d",A.data[n].v);
k=1;
}
}
if(k==0)
printf("%8d",k);
}
printf("\n\t\t");
}
}
void sumsparmatrix(sparmatrix A)
{
SPNode *p;
p=(SPNode*)malloc(sizeof(SPNode));
p->v=0;
int k;
k=0;
printf("\n\t\t");
for(int x=0;x<=A.rows-1;x++)
{
for(int y=0;y<=A.cols-1;y++)
{
for(int n=0;n<=A.terms;n++)
{
if((A.data[n].i==x)&&(A.data[n].j==y)&&(x==y))
{
p->v=p->v+A.data[n].v;
k=1;
}
}
}
printf("\n\t\t");
}
if(k==1)
printf("\n\t\t對角線元素的和：:%d\n",p->v);
else
printf("\n\t\t對角線元素的和為：:0");
}
int main()
{
int ch=1,choice;
struct sparmatrix A;
A.terms=0;
while(ch)
{
printf("\n");
printf("\n\t\t 稀疏矩陣的三元組系統 ");
printf("\n\t\t*********************************");
printf("\n\t\t 1------------創建 ");
printf("\n\t\t 2------------顯示 ");
printf("\n\t\t 3------------求對角線元素和");
printf("\n\t\t 4------------返回 ");
printf("\n\t\t*********************************");
printf("\n\t\t請選擇菜單號（0-3）:");
scanf("%d",&choice);
switch(choice)
{
case 1:
A=CreateSparmatrix();
break;
case 2:
ShowSparmatrix(A);
break;
case 3:
SumSparmatrix(A);
break;
default:
system("cls");
printf("\n\t\t輸入錯誤！請重新輸入！\n");
break;
}
if (choice==1||choice==2||choice==3)
{
printf("\n\t\t");
system("pause");
system("cls");
}
else
system("cls");
}
}
標簽：
數組
子系統
上傳時間：
2020-06-11
上傳用戶：ccccy
