American Gladiator,You are consulting for a game show in which n contestants are pitted against n gladiators in order to see which contestants are the best. The game show aims to rank the contestants in order of strength this is done via a series of 1-on-1 matches between contestants and gladiators. If the contestant is stronger than the gladiator, then the contestant wins the match otherwise, the gladiator wins the match. If the contestant and gladiator have equal strength, then they are “perfect equals” and a tie is declared. We assume that each contestant is the perfect equal of exactly one gladiator, and each gladiator is the perfect equal of exactly one contestant. However, as the gladiators sometimes change from one show to another, we do not know the ordering of strength among the gladiators.
標(biāo)簽： contestants consulting Gladiator are
上傳時(shí)間： 2013-12-18
上傳用戶：windwolf2000
Preparation of a function, even to the importation of n, the function call seeking +1/n 1/2+1/4+ .... When n is odd input, the function call 1/1+1/3+ ... +1/n (using function pointer)
標(biāo)簽： function Preparation importation the
上傳時(shí)間： 2014-01-21
上傳用戶：semi1981
--- --- --- ----UART0: 115200,8,n,1------------------------------- Embest S3CEV40 >Embest Info&Tech Co., Ltd. Embest Info&Tech Co., Ltd. Embest S3CEV40 >
標(biāo)簽： Embest 115200 UART 3CEV
上傳時(shí)間： 2013-11-30
上傳用戶：wqxstar
Embest S3C44B0X Evaluation Board RTC Test Example RTC Check(Y/N)? y Set Default Time at 2004-12-31 FRI 23:59:59 Set Alarm Time at 2005-01-01 00:00:01 ... RTC Alarm Interrupt O.K. ... Current Time is 2005-01-01 SAT 00:00:01 RTC Working now. To set date(Y/N)? y Current date is (2005,01,01, SAT). input new date (yy-mm-dd w): 5-2-23 3 Current date is: 2005-02-23 WED RTC Working now. To set time(Y/N)? y Current time is (00:00:21). To set time(hh:mm:ss): 19:32:5 Current Time is 2005-02-23 WED 19:32:
標(biāo)簽： Evaluation RTC S3C44B0X Default
上傳時(shí)間： 2014-01-03
上傳用戶：baiom
music算法運(yùn)用于波達(dá)方向的測定,波達(dá)方向的測定先現(xiàn)廣泛用于雷達(dá)等應(yīng)用中.music算法是個(gè)很成熟的算法,如今學(xué)者們就計(jì)算量,精確度上的問題又提出了很多的改進(jìn)算法.如下為 基本算法,可正確運(yùn)行
上傳時(shí)間： 2015-10-08
上傳用戶：1583060504
本程序可以在輸入n點(diǎn)后，判斷出這n個(gè)點(diǎn)中距離最近的兩個(gè)點(diǎn)
上傳時(shí)間： 2014-01-15
上傳用戶：yepeng139
此程序?qū)崿F(xiàn)八嗲DFT運(yùn)算,已調(diào)試通過! N為運(yùn)算的點(diǎn)數(shù),運(yùn)行后再輸入運(yùn)算對象,然后回車即可!
上傳時(shí)間： 2014-01-26
上傳用戶：anng
基于決策樹的n則交叉驗(yàn)證分類器 （決策樹程序直接調(diào)用matlab中的） crossvalidate.m N則交叉驗(yàn)證程序，N可選 NDT.mat 含9個(gè)國際公認(rèn)標(biāo)準(zhǔn)數(shù)據(jù)集，已做過標(biāo)么處理，可直接使用 專業(yè)
標(biāo)簽： crossvalidate matlab 決策樹 交叉驗(yàn)證
上傳時(shí)間： 2013-12-29
上傳用戶：784533221
假定已經(jīng)有許多應(yīng)用采用了程序1 - 1 5中所定義的C u r r e n c y類，現(xiàn)在我們想要對C u r r e n c y類 的描述進(jìn)行修改，使其應(yīng)用頻率最高的兩個(gè)函數(shù)A d d和I n c r e m e n t可以運(yùn)行得更快，從而提高應(yīng) 用程序的執(zhí)行速度。由于用戶僅能通過p u b l i c部分所提供的接口與C u r r e n c y類進(jìn)行交互，
上傳時(shí)間： 2015-10-11
上傳用戶：BIBI
鄰接矩陣類的根是A d j a c e n c y W D i g r a p h，因此從這個(gè)類開始。程序1 2 - 1給出了類的描述。程 序中，先用程序1 - 1 3中函數(shù)Make2DArray 為二組數(shù)組a 分配空間，然后對數(shù)組a 初始化，以描述 一個(gè)n 頂點(diǎn)、沒有邊的圖的鄰接矩陣，其復(fù)雜性為( n2 )。該代碼沒有捕獲可能由M a k e 2 D A r r a y 引發(fā)的異常。在析構(gòu)函數(shù)中調(diào)用了程序1 - 1 4中的二維數(shù)組釋放函數(shù)D e l e t e 2 D
標(biāo)簽： 矩陣
上傳時(shí)間： 2013-12-21
上傳用戶：lanjisu111
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