Simple GA code (Pascal code from Goldberg, D. E. (1989), Genetic Algorithms in Search, Optimization, and Machine Learning.)
標簽: D. E. code Optimization
上傳時間: 2014-12-07
上傳用戶:wlcaption
a Java toolkit for training, testing, and applying Bayesian Network Classifiers. Implemented classifiers have been shown to perform well in a variety of artificial intelligence, machine learning, and data mining applications.
標簽: Classifiers Implemented Bayesian applying
上傳時間: 2015-09-11
上傳用戶:ommshaggar
crc任意位生成多項式 任意位運算 自適應算法 循環冗余校驗碼(CRC,Cyclic Redundancy Code)是采用多項式的 編碼方式,這種方法把要發送的數據看成是一個多項式的系數 ,數據為bn-1bn-2…b1b0 (其中為0或1),則其對應的多項式為: bn-1Xn-1+bn-2Xn-2+…+b1X+b0 例如:數據“10010101”可以寫為多項式 X7+X4+X2+1。 循環冗余校驗CRC 循環冗余校驗方法的原理如下: (1) 設要發送的數據對應的多項式為P(x)。 (2) 發送方和接收方約定一個生成多項式G(x),設該生成多項式 的最高次冪為r。 (3) 在數據塊的末尾添加r個0,則其相對應的多項式為M(x)=XrP(x) 。(左移r位) (4) 用M(x)除以G(x),獲得商Q(x)和余式R(x),則 M(x)=Q(x) ×G(x)+R(x)。 (5) 令T(x)=M(x)+R(x),采用模2運算,T(x)所對應的數據是在原數 據塊的末尾加上余式所對應的數據得到的。 (6) 發送T(x)所對應的數據。 (7) 設接收端接收到的數據對應的多項式為T’(x),將T’(x)除以G(x) ,若余式為0,則認為沒有錯誤,否則認為有錯
上傳時間: 2014-01-16
上傳用戶:hphh
ApMl provides users with the ability to crawl the web and download pages to their computer in a directory structure suitable for a Machine Learning system to both train itself and classify new documents. Classification Algorithms include Naive Bayes, KNN
標簽: the provides computer download
上傳時間: 2015-11-29
上傳用戶:ywqaxiwang
We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.
標簽: represented integers group items
上傳時間: 2016-01-17
上傳用戶:jeffery
用游標的方法實現對稱差的計算,即 (A-B)+(B-A)
上傳時間: 2016-05-23
上傳用戶:遠遠ssad
一個用神經網絡方法實現人臉識別的程序,來源于CMU的machine learning 課程作業,具有參考價值
上傳時間: 2013-11-28
上傳用戶:515414293
詞法分析器 對輸入一個函數,并對其分析main() { int a,b a = 10 b = a + 20 }
上傳時間: 2013-12-20
上傳用戶:hfmm633
基因算法,用VC++或MATLAB,java等工具設計一程序計算任一個隨機產生的DNA基因表達式的有效長度和值 設隨機產生的基因表達式為: + Q - / b * b a Q b a a b a a b b a a a b
上傳時間: 2014-01-09
上傳用戶:aa54
函數再現機構設計 試設計一曲柄搖桿機構,再現函數 要求: 輸入構件的轉角范圍180°,輸出構件擺角范圍30°,即: 當輸入構件從a轉至a+90時,輸出構件從b轉至b+30 當輸入構件從a+90轉至a+180時,輸出構件從b+30轉至b
上傳時間: 2013-12-17
上傳用戶:英雄